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3 years ago

What would make oppositely charged objects attract each other more?

Chemistry

1 answer:

stepladder [879]3 years ago

3 0

<h2>Answer:</h2>

A). Increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object.

<h2>Explanation:</h2>

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HELP PLEASE HELP ME ONLY 2 QUESTIONS

lara [203]

311 are A 326 are O = 637

740 total

637/740 = 0.8608 = 0.861

1 person got an A and didn't study out of 7 total

so 1/7 and it is dependent

4 0

3 years ago

One mole of nitrogen dioxide has 6.02 x 10²³ nitrogen dioxide molecules. If nitrogen dioxide is made of one nitrogen atom and tw

marta [7]

Your answer, IMHO, is correct.

The detailed work is below:

1) to calculate the mass of one mole of nitrogen dioxide (NO₂): 14+2*16=46 (gr/mole);

it means, the mass of 1 mole of NO₂ is 46 gramms. Then

2) to calculate the space in milliliteres: V=mass/density=46/1.5=30.(6) (millilitres)≈31 ml.

3 0

4 years ago

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Sand (silicon dioxide) and coke (carbon) are combined to form silicon carbide (SiC), a compound used in high-strength ceramic ma

fenix001 [56]

Answer:

Mass = 235 g

Explanation:

Given data:

Mass of SiO₂ react = 352 g

Mass of silicon carbide formed = ?

Solution:

Chemical equation:

SiO₂ + 3C → SiC + 2CO

Number of moles of SiO₂:

Number of moles = mass/ molar mass

Number of moles = 352 g/ 60.08 g/mol

Number of moles = 5.86 mol

Now we will compare the moles of SiO₂ with SiC from balance chemical equation.

SiO₂ : SiC

1 : 1

5.86 : 5.86

Mass of SiC:

Mass = number of moles × molar mass

Mass = 5.86 mol × 40.11 g

Mass = 235 g

8 0

3 years ago

1) You have an aqueous solution where [OH-] = 1 x 10-4 mol/L.

Irina18 [472]

1. A. 1 x $10^{-10}$ x is the hydrogen ion concentration.

B. pH of the solution is 10

C. The solution is basic.

2. The molarity of NaCl in 2.8 litres of water is 1.18 M

3. 1.64 M is the molarity of new solution.

4. 0.64 M is the molarity of the acid or HCl used.

Explanation:

1. Data given [OH-] =1 x 10-4 mol/L.

A) $K_{w}$ = [ $H_{3}$ O+] [OH]- $K_{w}$ = 1× $10^{-14}$

[ $H_{3}$ O+]= 1× $10^{-14}$ ÷ 1 x 10-4

= 1 x $10^{-10}$ x is the hydrogen ion concentration.

B) pH =-log [ $H_{3}$ O+]

pH = -log[-1x $10^{-10}$ ]

pH = 10

c) pH value of 10 indicates that it is a basic solution because it is greater than 7 and on pH scale more than 7 value indicates basicity.

2. Molarity is calculated by the formula

Molarity = $\frac{number of moles}{volume}$

Number of moles can be calculated as:

n = $\frac{mass}{atomic mass of one mole of substance}$

n = $\frac{195}{58.44}$ ( atomic weight of NaCl is 58.44 gm/mole)

n= 3.33 moles

Now the molarity of NaCl in 2.8 litres of water is calculated as:

Molarity = $\frac{number of moles}{volume}$

M = $\frac{3.33}{2.8}$

M = 1.18

the molarity of NaCl in 2.8 litres of water is 1.18 M

3. Data given:

Initial volume of the HCl solution V1 = 152 ml, initial molarity M1 = 3

final volume of the diluted HCl V2= 750 ml, final molarity M2= Unknown

The initial and final volumes are converted into litres in calculation.

So, M1V1 = M2V2

3× $\frac{152}{1000}$ = M2 × $\frac{750}{1000}$

M2 = $\frac{0.75}{0.456}$

M2 = 1.64 M is the molarity of new solution.

4. In titration the formula used is: M acid x V acid = M base x V base

Volume of base V1= 20 ml Molarity of base M1 = 0.24 M

volume of the acid V2 = 31 ml Molarity of the acid = unknown

the volume will be converted to litres.

So applying the formula,

M acid x V acid = M base x V base

0.24 x $\frac{20}{1000}$ = Macid x $\frac{31}{1000}$

0.0048 = Macid x 0.031

Macid= $\frac{0.031}{0.048}$

M base= 0.64 M is the molarity of the acid or HCl used.

7 0

3 years ago

Wind blowing sediment against rock or land area, or sandblasting is called a. abrasion c. deflation b. deposits d. picking up PL

Andreas93 [3]

Answer:

abrasion

Explanation:

20 word limit why

4 0

3 years ago

Read 2 more answers