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3 years ago

The leader in student travel who provides educational tours at affordable prices is called?

Computers and Technology

1 answer:

jenyasd209 [6]3 years ago

3 0

Answer:

Juniour tours

Explanation

Juniour tours provide exceptional travel experience for their students in the educational travel market. They normally have customized packages that are usually customized and very affordable for the students. It offers tour escorts, food and accomodations, and round trip transportation.

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A network administrator receives a call from the sales department requesting ports 20 and 21 be opened on the company’s firewall

emmainna [20.7K]

Answer:Document the reason for the request, Follow the company’s approval process for the implementation

Explanation:

The port 20 and 21 are used for the FTP connection, so before opening port 20 and 21 it is necessary to abide by the company data security policy which includes documenting the reason for the request and following company's approval process for its implementation.

8 0

3 years ago

Need help asap please

Bumek [7]

Answer:

options is right

Explanation:

3 0

3 years ago

What are the first and the last physical memory addressesaccessible using

Misha Larkins [42]

Answer

For First physical memory address,we add 00000 in segment values.

For Last physical memory address,we add 0FFFF in segment values.

NOTE-For addition of hexadecimal numbers ,you first have to convert it into binary then add them,after this convert back it in hexadecimal.

a)1000

For First physical memory address, we add 00000 in segment value

We add 0 at the least significant bit while calculating.

10000 +00000 = 10000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

10000 +0FFFF =1FFFF (from note)

b)0FFF

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

0FFF0 +00000=0FFF0 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

0FFF0 +0FFFF =1FFEF (from note)

c)0001

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

00010 +00000=00010 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

00010 +0FFFF =1000F (from note)

d) E000

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

E0000 +00000=E0000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

E0000 +0FFFF =EFFFF (from note)

e) 1002

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

10020 +00000=10020 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

we add 0FFFF in segment value

10020 +0FFFF =2001F (from note)

6 0

3 years ago

Question: 4/8

Gemiola [76]

The generated test cases for the function assuming another developer coded the function is given below in a C++ program.

#include <iostream>

#include <iomanip>

#include <string>

using namespace std;

// define the data type "triangletype" with {values}

enum triangleType { scalene, isosceles, equilateral, noTriangle };

// Prototype function which returns the position of triangleType{value}

// Example: Scalene = 0, isosceles = 1, etc. These are zero indexed.

triangleType triangleShape(double a, double b, double c);

// Prototype function which takes the integer value of the

// triangle type and outputs the name of triangle

string shapeAnswer(int value);

int main() {

double inputA;

double inputB;

double inputC;

cout << "To determine whether a triangle is either:" << endl;

cout << setw(50) << " - Scalene" << endl; // Unequal in length

cout << setw(52) << " - Isosceles" << endl; // Two sides equal length

cout << setw(54) << " - Equilateral" << endl; // All sides equal

cout << setw(57) << " - Not a triangle" << endl;

cout << "Enter side A: ";

cin >> inputA;

cout << "Enter side B: ";

cin >> inputB;

cout << "Enter side C: ";

cin >> inputC;

cout << "The triangle is " << shapeAnswer(triangleShape(inputA, inputB, inputC)) << endl;

}

triangleType triangleShape(double a, double b, double c) {

triangleType answer;

if ( c >= (a + b) || b >= (a + c) || a >= (b + c) ) {

answer = noTriangle;

}

else if (a == b && b == c) {

answer = equilateral;

}

// Test the 3 options for Isosceles equality

else if ( (a == b) && (a != c) || (b == c) && (b != a) || (a == c) && (a != b) ) {

answer = isosceles;

}

else {

answer = scalene;

}

return answer;

}

string shapeAnswer(int value) {

string answer;

switch (value) {

case 0:

answer = "Scalene";

break;

case 1:

answer = "Isosceles";

break;

case 2:

answer = "Equilateral";

break;

case 3:

answer = "Not a triangle";

break;

default:

break;

}

return answer;

}