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ozzi
2 years ago
14

What is the simplified form of the expression (6^-4)^-9/6^6?​

Mathematics
2 answers:
sertanlavr [38]2 years ago
8 0

Answer:1/6 ^42

Step-by-step explanation:

aleksley [76]2 years ago
6 0

Answer:

(\frac{1}{1296} )^{\frac{729}{64} }

Step-by-step explanation:

I am assuming this problem reads (6^{-4}) ^{-\frac{9}{6}^6 }

  • So let's start on the outside and work our way towards the middle
  • Starting with the (-\frac{9}{6} )^{6}, this can be simplified to \frac{729}{64}

Now we have (6^{-4})^\frac{729}{64}

  • Now simplifying what is inside the parenthesis we get \frac{1}{1296}
  • Combining what we have the simplified for of the problem becomes: (\frac{1}{1296} )^{\frac{729}{64} }
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Find the general solution of the given higher-order differential equation. d3u dt3 + d2u dt2 − 2u = 0
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\dfrac{\mathrm d^3u}{\mathrm dt^3}+\dfrac{\mathrm d^2u}{\mathrm dt^2}-2u=0

This ODE has characteristic equation

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=(r(r+1)+(r+2))(r-1)=(r^2+2r+2)(r-1)=0

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u(t)=C_1e^t+C_2e^{(-1+i)t}+C_3e^{(-1-i)t}

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3 years ago
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y=3/4x+-3

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46?
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the point (4,0) lies on a circle with the center at the orgin. what is the area of the circle to the nearsest hundreth?
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50.27 units²

Step-by-step explanation:²

The standard equation of a circle with center at the origin is x² + y² = r², where r is the radius.  Substituting 4 for x and 0 for y yields 4² + 0² = r², so we see immediately that r = 4 units.

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