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2 years ago

Find the area of the shaded polygons NEED ASAP PLEASE!! THANK YOU

Mathematics

1 answer:

goldenfox [79]2 years ago

8 0

Answer:

168

Step-by-step explanation:

area of a trapezoid is

((a+b)/2)*h

((8+16)/2)*14

12*14 =

168

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John collected 17 leaves to feed his caterpillar collection if he wanted to split the leaves equally amongst the four cages how

Papessa [141]

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It lies between the numbers 4 and 5

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3 years ago

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Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12

miskamm [114]

keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

$\bf 3y-x=-12\implies 3y=x-12\implies y=\cfrac{x-12}{3}\implies y = \cfrac{x}{3}-\cfrac{12}{3} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{3}}x-4\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 1/3 and runs through (18,2)

$\bf (\stackrel{x_1}{18}~,~\stackrel{y_1}{2})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{18}) \\\\\\ y-2=\cfrac{1}{3}x-6\implies y=\cfrac{1}{3}x-4$

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2 years ago

M=-3/7 ; (-5,6) what is the equation of the line

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Y - 6 = -3/7(x + 5)

y - 42/7 = -3/7x - 15/7

y = -3/7x + 27/7

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olga nikolaevna [1]

Answer:

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