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In-s [12.5K]
3 years ago
10

Using the table of standard formation enthalpies that you'll find under the ALEKS Data tab, calculate the reaction enthalpy of t

his reaction under standard conditions: 2C,H (9)+70,(9) 400 (9)+6,000 OO Round your answer to the nearest kJ. E n​
Chemistry
1 answer:
Natasha2012 [34]3 years ago
7 0
Hard question !! Is this math .. if not then oh okay cause I’m bad at math but good at everything else so let me think about it !
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Which statement is true?
dimulka [17.4K]

Answer:

A I think

Explanation:

6 0
3 years ago
how many milliliters of a stock solution of 2.00M KNO3 would you need to prepare 100.0mL of 0.150M KNO3?
larisa86 [58]
The answer is 7.5 ml
3 0
3 years ago
An ionic bond forms when atoms blank electrons
8_murik_8 [283]

Answer:

An ionic bond forms when atoms transfer electrons.

Explanation:

Ionic bonds are formed when atoms transfer electrons. (In contrast, covalent bonds are formed when atoms share electrons.)

There's a distinction between the two: when two atoms react to form an ionic bond, one atom would completely lose one electron, while the other would completely gain that electron. The atom that loses the electron becomes a positively-charged ion called a cation, whereas the atom that gains the electron becomes a negatively-charged ion called an anion.

For example, consider the reaction between a sodium \rm Na atom and a chlorine \rm Cl atom: \rm Na + Cl \to NaCl.

When the sodium atom and the chlorine atom encounter, the sodium atom would lose one electron to form a positively-charged sodium ion, \rm Na^{+}. The chlorine atom would gain that electron to form a negatively-charged chlorine ion \rm Cl^{-}.

These two ions will readily attract each other because of the opposite electrostatic charges on them. This electrostatic attraction (between two ions of opposite charges) is an ionic bond.

Overall, it would appear as if the sodium \rm Na atom transferred an electron to the chlorine \rm Cl atom to form an ionic bond.

In contrast, when two atoms react to form a covalent bond, they share electrons without giving any away completely. Therefore, it is possible to break certain covalent bonds apart (using a beam of laser, for example) and obtain neutral atoms.

On the other hand, when an ionic bond was broken, the result would be two charged ions- not necessarily two neutral atoms. The electron transfer could not be reversed by simply breaking the bond.

For example, when table salt \rm NaCl is melted (at a very high temperature,) the ionic bond between the sodium ions and chloride ions would (mostly) be broken. However, doing so would only generate a mixture of \rm Na^{+} and \rm Cl^{-} ions- not sodium and chlorine atoms.

7 0
2 years ago
Will mark the brainiest later for correct answers! Please show work.
Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}

a. moles in 14.08 g of C_{12}H_{22}O_{11} = \frac{14.08g}{342.3g/mol}=0.04113moles

molecules in 14.08 g of C_{12}H_{22}O_{11} = 0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}

b. moles in 17.75 g of NaCl = \frac{17.75g}{58.5g/mol}=0.3034moles

molecules in 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

formula units 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

c. moles in 20.06 g of  CuSO_4.5H_2O= \frac{20.06g}{249.68g/mol}=0.08034moles

formula units in 20.06 g of  CuSO_4.5H_2O= 0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}

7 0
3 years ago
What mass of Na2SO4 is needed to make 2.5L of 2.0M solution? (Na=23g; S=32g; O=16g)
zaharov [31]
The molar mass of Na₂SO₄ - 
2 x Na - 2 x23 = 46
1 x S - 1 x 32 = 32 
4 x O - 4 x 16 = 64 
total = 46 + 32 + 64 = 142 g/mol
the molarity of solution - 2.0 M 
in 1 L of solution , 2.0 moles
Therefore in 2.5 L - 2 mol/L x 2.5 L = 5 mol
then the mass of Na₂SO₄ required = 142 g/mol x 5 mol = 710 g
8 0
3 years ago
Read 2 more answers
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