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vodka [1.7K]
3 years ago
12

In ΔXYZ, the measure of ∠Z=90°, YZ = 43 feet, and XY = 79 feet. Find the measure of ∠Y to the nearest degree.

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

57

Step-by-step explanation:

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25 point question below
kotykmax [81]

Answer:

Image point → (13, -3)

Step-by-step explanation:

Rule for the translation of a point (x, y) by shifting 'a' units right and 'b' units down is,

(x, y) → (x + a, y - b)

If a point (-1, -8) has been translated by 4 units right and 5 units down,

(-1, -8) → (-1 + 4, -8 - 5)

          → (3, -13)

Followed by reflection across a line y = -x.

Rule for the reflection of a point (x, y) about a y = -x is,

(x, y) → (-y, -x)

Therefore, reflection of the point (3, -13) will produce an image point as,

(3, -13) → (13, -3)

Hence, image point by the transformations given will be (13, -3).

7 0
3 years ago
Read 2 more answers
What is the value of 7 to the fifth power? A. 35 B. 78,125 C. 2,401 D. 16,807
podryga [215]
D because all you really have to do is 7*7*7*7*7
5 0
3 years ago
Read 2 more answers
Can I plz have some help​
ella [17]
I think it is 63 because a triangle equals 180
6 0
3 years ago
A running track consists of two parallel lines that are connected at each end but the curved boundary of a semicircle. The paral
saveliy_v [14]

Answer:

The area inside the running track is 248.5 m².

Step-by-step explanation:

The area inside the running track is given by the sum of the area of a rectangle and the area of a semicircle:

A_{t} = A_{r} + 2A_{c}                

A_{t} = x*(2r) + 2*(\frac{\pi r^{2}}{2})      

Where:

x: is one side of the rectangle = 30 m            

r: is the radius = half of the other side of the rectangle = 7/2 m = 3.5 m

Hence, the total area is:

A_{t} = 30*7 + \pi (3.5)^{2} = 248.5 m^{2}                            

Therefore, the area inside the running track is 248.5 m².

I hope it helps you!                                                    

3 0
3 years ago
Jessica is a custodian at Oracle Arena. She waxes 20 \text{ m}^220 m 2 20, space, m, start superscript, 2, end superscript of th
Evgesh-ka [11]

Given that Jessica is a custodian at Oracle Arena.

She waxes 20 square meters space of the floor in 5/3 of an hour. Jessica waxes the floor at a constant rate means rate will remain fixed for any hour.

Now we have to find about how many square meters can she wax per hour.

To find that we just need to divide 20 squaer meters by 5/3 hours

\frac{20}{\left(\frac{5}{3}\right)}

=20\cdot\frac{3}{5}

=\frac{60}{5}

=12

Hence final answer is 12 square meters can she wax per hour.

Which can also be written as 12m^2 per hour.

4 0
3 years ago
Read 2 more answers
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