Answer: 92
Step-by-step explanation:
From the little marks on the sides, we can see that YZ is the midpoint segment.
YZ is half of VX
12.2 is the answer.
Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°
To Find: The length of the park's boundary to the nearest yard.
Calculation:
The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc
or, (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)
or, (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 209.33 yards
or, (P) = 309.33 yards ≈309 yards
Hence, the option D:309 yards is the correct option.
KE = 0 (because velocity is 0)
PE = mgh = 2kg*9.8m/s^2*40m= 784 joule
<u>Explanation:</u>
KE stands for kinetic energy. In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.
Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. Since in this case, the building is still and therefore it does not have any kind of kinetic energy because there is not acceleration.
Answer:
The picture is 4.25 inches from the side of the paper
Step-by-step explanation:
- Taylor wants to center a 3.5 inch picture on a piece of paper that is
12 inches wide
- Lets think about that he want to put the picture in the center of the
paper, then divide the length of the paper into two equal parts and the
picture into two equal part
∵ The width of the paper is 12 inches
∵ 12 ÷ 2 = 6 inches
∵ The width of the picture is 3.5 inches
∵ 3.5 ÷ 2 = 1.75
- Now lets subtract from 6 inches (half paper) 1.75 inches (half picture)
to find the distance between the side of the paper and the picture
∵ 6 - 1.75 = 4.25
∴ The distance from the side of the paper to the picture is 4.25 inches
* <em>The picture is 4.25 inches from the side of the paper</em>
* Look to attached figure for more understand
