final velocity = initial
velocity + (acceleration x time) <span>
3.9 m/s = 0 m/s + (acceleration x 0.11 s)
3.9 m/s / 0.11 s = acceleration
30.45 m/s^2 = acceleration
distance = (initial velocity x time) +
1/2(acceleration)(time^2)
distance (0 m/s x 0.11 s) + 1/2(30.45 m/s^2)(0.11s ^2)
<span>distance = 0.18 m</span></span>
The new force between the charges when the distance become 2d will be F'=4F
<h3>What is electrostatic force?</h3>
When two charged particles are separated by the distance d then the force of attraction or repultion acts on the charged particle depending upon the nature of the charge whether it is positive or negative.
The formula for the electrostatic force is given by
Now if the value of d becomes 2d then the formula will become:
Hence the new force between the charges when the distance become 2d will be F'=4F
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187500 Joules of work must be done to the 3000 kg car to change its speed from 10 m/s to 15 m/s.
Explanation:
Work is the measurement of the force on an object that overcomes a resisting force (such as friction or gravity) times the distance the object is moved. If there is no distance, there is no work, no matter what the effort.
Work done = Force * displacement
When you apply enough force on an object to overcome a resistive force, such that you move that object, you are doing work on that object. There is a relationship between that work and mechanical energy.
When an object is accelerated, you are doing work against inertia, such that the work equals the change in kinetic energy of the object.
Work done = Change in K.E
In the given case:
mass = m = 3000 kg
initial velocity = v₁ = 10 m/s
final velocity = v₂ = 10 m/s
Work = W = (1/2)m(v₂)² - (1/2)m(v₁)²
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The distance traveled by the student's boxcar that starts from rest and reaches an acceleration and velocity of 13.1 m/s² and 24.5 m/s, respectively, is 22.9 meters.
We can find the distance traveled by the boxcar with the following kinematic equation:
Where:
: is the final velocity = 24.5 m/s
: is the initial velocity = 0 (it starts from rest)
a: is the acceleration = 13.1 m/s²
d: is the distance =?
By solving the above equation for <em>d</em>, we have:
Therefore, the boxcar will travel 22.9 meters.
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Answer:
213 s
Explanation:
Slope is the ratio of change in vertical distance to change in horizontal distance.
Slope = vertical height / horizontal height
Therefore:
6.4% = vertical height / 12.42
vertical height = 6.4% * 12.42
vertical height = 0.8 miles
The distance travelled by the car (s) is:
s² = 0.8² + 12.42²
s² = 154.9
s = 12.45 miles
Acceleration (a) = 2.93 ft/s^2 = 0.00055 mile/s²
initial velocity (u) = 0, final velocity = 203 mph
Using:
s = ut + 0.5at²
12.45 = 0.5(0.00055)t²
t =213 s