Question

Given the velocity v= ds dt and the initial position of a body moving along a coordinate line, find the body's position at time t

Answer 1

For  the​ body's position at time t  is mathematically given as

s(t)=4.9t^2+5t+16

What is the​ body's position at time t

Generally, the equation for the velocity is mathematically given as

v=ds/dt

v=9.8t+5 as velocity

s=4.9t^2+5t+c

s(0)=16

16=c

s(t)=4.9t^2+5t+16

In conclusion the​ body's position at time t

s(t)=4.9t^2+5t+16

Read more about Speed

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Answer 2

The body position at the given time t is s = 4.9t² + 5t + 16 if the velocity v= ds/dt and the initial position of a body moving along a coordinate line.

What is the distance?

A numerical representation of the distance between two items or locations is called distance. A physical length or an approximation based on other considerations in physics or common usage can be referred to as distance.

We have:

$\rm v = \frac{ds}{dt}$

$\rm v = 9.8t+5$  is the velocity

$\rm s = 4.9t^2+5t+c$ is the speed

At t = 0 s(0) = 16

16 = c

$\rm s = 4.9t^2+5t+16$

Thus, the body position at the given time t is s = 4.9t² + 5t + 16 if the velocity v= ds/dt and the initial position of a body moving along a coordinate line.

Learn more about the distance here:

brainly.com/question/26711747

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