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Dimas [21]
3 years ago
15

A horse runs a race on a oval track and starts and ends at the same point. He runs one mile track in 7 minutes.

Physics
1 answer:
Sergeeva-Olga [200]3 years ago
4 0

Answer:

speed = 8.57mph while v = 0 mph

Explanation:

The horse is running 1 mile in 7 minutes. Then for a total of 1 hour, 60 minutes, the horse should be able to run a distance of

\frac{1*60}{7} = \frac{60}{7} = 8.57mph

So the horse speed is 8.57 miles per 60 minutes, or 8.57 mph (mile per hour). But if he ends up at the same point as before int he oval track, one can argue that the displacement is 0, and so is its velocity.

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Covalent bonds tend to make atoms more stable by helping them
Lelechka [254]
Achieve a full outer shell
6 0
3 years ago
Does gravity exist between a pencil on a coffee mug
DIA [1.3K]

Answer:

Yes it does

Explanation:

Gravity is pushing down on the pencil but the coffee mug is also pushing the pencil up with the same amount of force so they both don't move

5 0
3 years ago
(a) If two sound waves, one in a gas medium and one in a liquid medium, are equal in intensity, what is the ratio of the pressur
GarryVolchara [31]

Answer:

(a) The ratio of the pressure amplitude of the waves is 43.21

(b) The ratio of the intensities of the waves is 0.000535

Explanation:

Given;

density of gas, \rho _g = 2.27 kg/m³

density of liquid, \rho _l = 972 kg/m³

speed of sound in gas, C_g = 376 m/s

speed of sound in liquid, C_l = 1640 m/s

The of the sound wave is given by;

I = \frac{P_o^2}{2 \rho C} \\\\P_o^2 = 2 \rho C I\\\\p_o = \sqrt{2 \rho CI}

Where;

P_o is the pressure amplitude

P_o_g= \sqrt{2 \rho _g C_gI} -------(1)\\\\P_o_l= \sqrt{2 \rho _l C_lI}---------(2)\\\\\frac{P_o_l}{P_o_g} = \frac{\sqrt{2 \rho _l C_lI}}{\sqrt{2 \rho _g C_gI}} \\\\\frac{P_o_l}{P_o_g} = \sqrt{\frac{2 \rho _l C_lI}{2 \rho _g C_gI} }\\\\ \frac{P_o_l}{P_o_g} = \sqrt{\frac{ \rho _l C_l}{ \rho _g C_g} }\\\\ \frac{P_o_l}{P_o_g} = \sqrt{\frac{ (972)( 1640)}{ (2.27)( 376)} }\\\\\frac{P_o_l}{P_o_g} = 43.21

(b) when the pressure amplitudes are equal, the ratio of the intensities is given as;

I = \frac{P_o^2}{2 \rho C}\\\\I_g = \frac{P_o^2}{2 \rho _g C_g}-------(1)\\\\I_l = \frac{P_o^2}{2 \rho _l C_l}-------(2)\\\\\frac{I_l}{I_g} = (\frac{P_o^2}{2 \rho _l C_l})*(\frac{2\rho_gC_g}{P_o^2} )\\\\\frac{I_l}{I_g} = \frac{\rho _gC_g}{\rho_lC_l} \\\\\frac{I_l}{I_g} = \frac{(2.27)(376)}{(972)(1640)}\\\\ \frac{I_l}{I_g} = 0.000535

3 0
3 years ago
a baseball player is dashing toward home plate with a speed of 200 feet per hour. When he decides to hit the dirt. he slides for
Serggg [28]

To solve this problem we will use the kinematic formula for the final velocity.


V_f_x = V_0_x + a_xt


The final speed is 0 at the moment the player stops.


The time until it stops is 1.3 s


The initial speed is 200 feet / s  Note (check the speed units in the problem statement, 200ft / s is very much and 200ft / h is very small)

Then, we clear the formula.


a_x = \frac{(Vfx-V0x)}{t}\\ a_x = \frac{(0-200)}{1.3}\\ a_x = -153.5 ft / s ^ 2

Because the player is slowing down, the acceleration goes in the opposite direction to the player's movement, and that is why it is negative.



To answer part b) we use the following formula.


Vf ^ 2 = Vo ^ 2 + 2a * (x_2 - x_1)\\\\ (x_2 - x_1)= \frac{(V_f ^ 2-V_0 ^ 2)}{2a}\\\\ (x_2 - x_1)= \frac{(0-200 ^ 2)}{- 2 * 153.5}\\\\ (x_2 - x_1)= 130.29 feet

8 0
3 years ago
Can the tangent line to a velocity vs. time graph ever be vertical? Explain.
34kurt

Answer:

No. Because it would correspond to zero Instantaneous acceleration.

Explanation:

hope this helps

7 0
3 years ago
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