Answer:
0.125 volts
Explanation:
The induced emf can be sufficient to stimulate neuronal activity.
One such device generates a magnetic field within the brain that rises from zero to 1.5 T in 120 ms.
We need to find the induced emf within a circle of tissue of radius 1.6 mm and that is perpendicular to the direction of the field. The formula for the induced emf is given by :

Where
is magnetic flux
So,

So, the induced emf is equal to 0.125 volts.
The movements of the tectonic plates
Number 1. The medium around the wire
Answer:
The atom becomes a positively charged ion.
Explanation:
- The building blocks of an atom are protons, neutrons, and electrons.
- The protons and neutrons present in the core of the atom are called nucleus.
- The electrons are scattered in an ordered way around the nucleus.
- The protons are positively charged and the electrons are negatively charged particles. The neutrons do not possess any charges.
- Binding energy is supplied to the atom to remove an electron.
- It is possible to remove the electrons of the lighter elements.
- When an electron is removed from the hydrogen atom. It becomes positively charged ion or simply proton.
- When all of the electrons are removed from the helium atom, it becomes a positively charged α particle.
- It is practically very difficult to remove all of the electrons from the heavier elements.
- When all of the electrons are removed from an atom it becomes an unstable positively charged ion.
Answer:
0.191 s
Explanation:
The distance from the center of the cube to the upper corner is r = d/√2.
When the cube is rotated an angle θ, the spring is stretched a distance of r sin θ. The new vertical distance from the center to the corner is r cos θ.
Sum of the torques:
∑τ = Iα
Fr cos θ = Iα
(k r sin θ) r cos θ = Iα
kr² sin θ cos θ = Iα
k (d²/2) sin θ cos θ = Iα
For a cube rotating about its center, I = ⅙ md².
k (d²/2) sin θ cos θ = ⅙ md² α
3k sin θ cos θ = mα
3/2 k sin(2θ) = mα
For small values of θ, sin θ ≈ θ.
3/2 k (2θ) = mα
α = (3k/m) θ
d²θ/dt² = (3k/m) θ
For this differential equation, the coefficient is the square of the angular frequency, ω².
ω² = 3k/m
ω = √(3k/m)
The period is:
T = 2π / ω
T = 2π √(m/(3k))
Given m = 2.50 kg and k = 900 N/m:
T = 2π √(2.50 kg / (3 × 900 N/m))
T = 0.191 s
The period is 0.191 seconds.