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Julli [10]
3 years ago
8

If we have less power, we most likely have

Physics
2 answers:
katrin [286]3 years ago
3 0
<span>the same amount of work being done over a longer period of time.</span>
DENIUS [597]3 years ago
3 0
We must have more power.
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Two steamrollers begin 115 mm apart and head toward each other, each at a constant speed of 1.10 m/sm/s . At the same instant, a
NeX [460]

Answer:

The distance of fly travel is 115.06 m.

Explanation:

Given that,

Distance = 115 mm

Speed = 1.10 m/s

Speed of fly = 2.20 m/s

We need to calculate the relative speed

Using formula of relative speed

v=v_{1}+v_{2}

Put the value into the formula

v=1.10+1.10

v=2.20\ m/s

We need to calculate the time for the two steamrollers to meet each other

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{115}{2.20}

t=52.3\ sec

We need to calculate the distance of fly travel

Using formula of distance

d=vt

Put the value into the formula

d=2.20\times52.3

d=115.06\ m

Hence, The distance of fly travel is 115.06 m.

3 0
3 years ago
A car traveled 176 miles on 6.4 gallons of fuel the car averaged how many miles per gallon
earnstyle [38]
It would be 27.5 miles per gallon
3 0
3 years ago
Scientists can help us understand the impact of human activities on the environment. True or false?
zhannawk [14.2K]

Answer:

True

Explanation:

hope it will help you

5 0
2 years ago
The position vector of a particle of mass 1.65 kg as a function of time is given by = (6.00 î + 4.15 t ĵ), where is in meters an
SashulF [63]

Answer:

 L = 41.09 Kg m2 / s      The angular momentum does not depend on the time

Explanation:

The definition of angular momentum is

        L = r x p

Where blacks indicate vectors

Let's apply this definition our case. Linear momentum

      p = m v

Let's replace

      L = m r x v

The given function is

      x = 6.00 i ^ + 4.15 t j ^

We look for speed

     v = dx / dt

     v = 0 + 4.15 j ^

To evaluate the angular momentum one of the best ways is to use determinants

     L = m \left[\begin{array}{ccc}i&j&k\\6&4.15t&0\\0&4.15&0\end{array}\right]

      L = m 6 4.15 k ^

The other products give zero

Let's calculate

      L = 1.65 6 4.15 k ^

      L = 41.09 Kg m2 / s

The angular momentum does not depend on the time

7 0
3 years ago
A rocket moves upward, starting from rest with an acceleration of 25.4 m/s^2 for 3.39 s. It runs out of fuel at the end of the 3
kolbaska11 [484]

Explanation:

Initial speed of the rocket, u = 0

Acceleration of the rocket, a=25.4\ m/s^2

Time taken, t = 3.39 s

Let v is the final velocity of the rocket when it runs out of fuels. Using the equation of kinematics as :

v=u+at

v=25.4\times 3.39=86.10\ m/s    

Let x is the initial position of the rocket. Using third equation of kinematics as :

v^2=u^2+2ax_o

x_o=\dfrac{v^2}{2a}

x_o=\dfrac{86.10^2}{2\times 25.4}=145.92\ m  

Let x_o is the position at the maximum height. Again using equation of motion as :

v^2-u^2=2a(x-x_o)

Now a=-g and v and u will interchange

u^2=2g(x-x_o)

x=x_o+\dfrac{u^2}{2g}

x=145.92+\dfrac{(86.10)^2}{2\times 9.8}

x = 524.14 meters

Hence, this is the required solution.

5 0
3 years ago
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