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I am Lyosha [343]
2 years ago
13

A deck of cards has all 12 face cards removed. If a card is drawn at random, what are the odds against drawing a card that is a

prime number? Note: Prime means the only numbers divisible are 1 and itself.
3 to 2
2 to 5
3 to 5
2 to 3
Mathematics
2 answers:
sergij07 [2.7K]2 years ago
6 0
The answer is 2 to 5
kap26 [50]2 years ago
4 0

Answer:

the answer is A 3 to 2

Step-by-step explanation:

but if it's wrong I'm sorry but if it's right I'm happy for you

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-7x is less than or equal to -21
julsineya [31]
The answer is x=3
if you divide each by -7 to isolate x, it’s equal to positive three because 2 negatives make a positive
6 0
2 years ago
1/4d=1/5g(g+e)-h <br> solve for d<br> Please show your work.
loris [4]

Answer:

See below

Step-by-step explanation:

To solve for d, multiply both sides of the equal sign by 4.

4(1/4d) = 4 (1/5g(g+e)-h)

4/4d = 4(1/5g^{2} + 1/5ge - h)

d = 4/5g^{2} + 4/5ge - 4h

5 0
2 years ago
HELP PLEASE 15 POINTS
Step2247 [10]

Angle C, it sounds obvious but they correspond to the angle in the same order as them, as both E and C are in the middle it has to be C.

6 0
3 years ago
Read 2 more answers
De moirve's <br> (√3-i ÷ √3+i)^6 = 1
bulgar [2K]

(√3 - <em>i </em>) / (√3 + <em>i</em> ) × (√3 - <em>i</em> ) / (√3 - <em>i</em> ) = (√3 - <em>i</em> )² / ((√3)² - <em>i</em> ²)

… = ((√3)² - 2√3 <em>i</em> + <em>i</em> ²) / (3 - <em>i</em> ²)

… = (3 - 2√3 <em>i</em> - 1) / (3 - (-1))

… = (2 - 2√3 <em>i</em> ) / 4

… = 1/2 - √3/2 <em>i</em>

… = √((1/2)² + (-√3/2)²) exp(<em>i</em> arctan((-√3/2)/(1/2))

… = exp(<em>i</em> arctan(-√3))

… = exp(-<em>i</em> arctan(√3))

… = exp(-<em>iπ</em>/3)

By DeMoivre's theorem,

[(√3 - <em>i </em>) / (√3 + <em>i</em> )]⁶ = exp(-6<em>iπ</em>/3) = exp(-2<em>iπ</em>) = 1

7 0
3 years ago
NEED HELPPP #2 PLZZZZZZZ
Gelneren [198K]

Answer:

Step-by-step explanation:

p > 9

Hope that helps!

8 0
2 years ago
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