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solmaris [256]
3 years ago
6

Classify each titration curve as representing a strong acid titrated with a strong base, a strong base titrated with a strong ac

id, a weak acid titrated with a strong base, a weak base titrated with a strong acid, or a polyprotic acid titrated with a strong base. A. Strong acid/ strong base.B. Strong base/ strong acid.C. Weak acid/ strong base.D. Weak base/ strong acid.E. Polyprotic acid/ strong base.
Chemistry
1 answer:
Ilya [14]3 years ago
3 0

Answer:

Acid base titration curves shows the pH at equivalence point

Explanation:

Since the images were not shown, I will proceed to give a general description of the following acid-base titration curves:

In a strong acid-strong base titration, the acid and base will react to form a neutral solution. At the equivalence point of the reaction, hydronium (H+) and hydroxide (OH-) ions will react to form water, leading to a pH of 7.

The titration curve reflects the strengths of the corresponding acid and base. If one reagent is a weak acid or base and the other is a strong acid or base, the titration curve is irregular, and the pH shifts less with small additions of titrant near the equivalence point.

Polyprotic acids are able to donate more than one proton per acid molecule, in contrast to monoprotic acids that only donate one proton per molecule. In the titration curve of a polyptotic acid and a strong base, The curve starts at a higher pH than a titration curve of a strong base. There is always a steep climb in pH before the first midpoint. Gradually, the pH increases until it passes the midpoint; Right before the equivalence point there is a very sharp increase in pH.

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A chemist prepares a solution by adding 258 mg of K2Cr2O7 (MW = 294.19 g/mol ) to a volumetric flask, and then adding water unti
Maksim231197 [3]

Answer: Molarity of the prepared solution is 1.75\times 10^{-3}mole/L

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

V_s = volume of solution in ml = 500 ml

moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{0.258g}{294.19g/mol}=8.77\times 10^{-4}mol

Now put all the given values in the formula of molarity, we get

Molarity=\frac{8.77\times 10^{-4}moles\times 1000}{500ml}=1.75\times 10^{-3}mole/L

Thus molarity of the prepared solution is 1.75\times 10^{-3}mole/L

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Which is a more reactive chemical, Ca or Ga?
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Ga’s electronegativity is 1.81 and Ca’s is 1.00 . Does that help?
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Calculate the solubility (in g/L) of CaSO 4 ( s ) CaSO4(s) in 0.400 M Na 2 SO 4 ( aq ) at 25 ° C 0.400 M Na2SO4(aq) at 25°C. The
Allushta [10]

Explanation:

Ionization equation for CaSO_{4} is as follows.

     CaSO_{4} \rightarrow Ca^{2+} + SO^{2-}_{4}

        s              s           s

Now, the expression for the solubility product is as follows.

          K_{sp} = [Ca^{2+}][SO^{2-}_{4}]

                = s \times s

                = s^{2}

As the concentration of Na_{2}SO_{4} is given as 0.4 M.

So,  [Na_{2}SO_{4}] = [SO^{2-}_{4}] = 0.4 M

Putting the given values as follows.

           K_{sp} = [Ca^{2+}][SO^{2-}_{4}]

     4.93 \times 10^{-5} = [Ca^{2+}] \times 0.4

              [Ca^{2+}] = 12.325 \times 10^{-5}[/tex]

Hence, the solubility of CaSO_{4} in Na_{2}SO_{4} is 12.325 \times 10^{-5}.

Therefore, solubility of CaSO_{4} in g/ml as follows.

        12.325 \times 10^{-5} \times 136 g/mol

           = 0.0167 g/L

Thus, we can conclude that solubility of CaSO_{4} is 0.0167 g/L.

4 0
3 years ago
When you have a two-layer mixture of water and tert-butyl methyl ether, what physical property of these liquids assures you that
mash [69]

Answer:

The density.

Explanation:

The density is an intensive property of fluids, defined as mass divided by volume.

This property is directly related to the intermolecular forces that are present in the substance: the stronger the intermolecular forces, the higher the density will be, and viceversa. Therefore, organic fluids usually have lower densities than water, because <u>the intermolecular forces in organic fluids are not as strong as in the intermolecular forcer in water</u> (water has very stable hydrogen bonds, whereas organic fluids have van der Waals, weaker than hydrogen bonds).

The liquid that has the lower density will be the the liquid that is on the top layer. In this case, the organic compound tert-butyl methyl ether will be on top of water.

5 0
3 years ago
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