The answer would be 6.20 so they would be equivalent
The -1 charge means that there is one more electron than protons, so there are 85 protons
Answer:
The concentration of glucose 95.4 mg/dL:
Explanation:
![Molarity = 1000 \times \text{milliMolarity}](https://tex.z-dn.net/?f=Molarity%20%3D%201000%20%5Ctimes%20%5Ctext%7BmilliMolarity%7D)
Concentration of glucose in blood = 5.3 milli Molar
This means that 5.3 milli moles are present in 1 l of solution.
5.3 milli moles = 0.0053 moles
So, from this we can say that 0.0053 moles of glucose are present in 1 L solution.
Mass of 0.0053 moles of glucose :
= 0.0053 mol × 180 g/mol = 0.954 g
(1 g = 1000 mg)
0.954 g = 954 mg
945 milli grams in 1 liter of the solution.
(1 L = 10 dL)
The concentration of glucose in mg/dL:
![\frac{945 mg}{10 dL}=94.5 mg/dL](https://tex.z-dn.net/?f=%5Cfrac%7B945%20mg%7D%7B10%20dL%7D%3D94.5%20mg%2FdL)
In electrophilic aromatic substitution reactions the hydroxyl group is an o,p-director because: hydroxyl group donates the electron density to the ring by induction and destabilizes the meta sigma complex and by resonance and it stabilizes the ortho and para sigma complexes of aromatic ring .
Most ring activators have atoms with unshared electron pairs directly attached to a carbon atom of the benzene ring . For example, the — OH group has two pairs of unshared electrons on the oxygen atom , which will form a bond to a carbon atom of the benzene ring . Thus , the — OH group will be an activating group in electrophilic aromatic substitution reactions .
to learn more about electrophilic aromatic substitution reactions please click here ,
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Answer:
D. 0.36 g
Explanation:
When a gas is collected over water, the total pressure is the sum of the pressure of the gas and the pressure of the water vapor.
Ptotal = Pwater + PN₂
PN₂ = Ptotal - Pwater = 730 torr - 23.76 torr = 706 torr
We can find the mass of N₂ using the ideal gas equation.
![P.V=n.R.T=\frac{m}{M} .R.T\\m=\frac{P.V.M}{R.T} =\frac{730torr.0.340L.28g/mol}{(0.08206atm.L/mol.K).298K} .\frac{1atm}{760torr} =0.36g](https://tex.z-dn.net/?f=P.V%3Dn.R.T%3D%5Cfrac%7Bm%7D%7BM%7D%20.R.T%5C%5Cm%3D%5Cfrac%7BP.V.M%7D%7BR.T%7D%20%3D%5Cfrac%7B730torr.0.340L.28g%2Fmol%7D%7B%280.08206atm.L%2Fmol.K%29.298K%7D%20.%5Cfrac%7B1atm%7D%7B760torr%7D%20%3D0.36g)