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qwelly [4]
3 years ago
9

Which physical state of matter exhibits the greatest change in volume with changes or temperature or pressure?

Chemistry
1 answer:
katovenus [111]3 years ago
6 0
<span>It’s the gas physical state that shows the greatest change in volume and changes in temperature or pressure. Because gas is the matter that is composed of loose particles but can be compressed. Since gas contains loose molecules, the molecules can freely move in a certain object, so when physical change happens, it exhibit greatest change. Gas also follow the shape of its container and can expand in order to fill its container. It has no definite volume or shape. </span>



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can someone help me more clearly understand the difference between heterogeneous and homogeneous? Give an example of each plz.
const2013 [10]
Heterogenous mixtures are unevenly mixed. Like oil and vinegar in vinaigrette if it is not emulsified well enough and they separate. Any case where two things are not evenly distributed within each other.

Homogenous mixtures are evenly mixed throughout. Like salt water or kool-aid (when it's mixed).

Hope this helps!
3 0
3 years ago
If the ph of a solution is 6.2 what would the poh be
horsena [70]
PH + poH = 14
6.2 +poH = 14
poH = 7.8
7 0
3 years ago
Read 2 more answers
I need chemistry help! How would I set up these problems?
Bond [772]

Answer: -

1) 8.33 minutes

2) 118.39 in/ s

180.43 m/min

10.83 km/ hr

Explanation: -

Speed of light = 3 x 10⁸ m/s

Distance of the earth from the sun= 93 million miles

We know 1 million = 1,000,000

Also 1 mile = 1609 m

Distance of the earth from the sun= 93 million miles

= 93,000,000 miles.

= 1.5 x 10^{11} m

Time taken = \frac{Distance}{Speed}

= \frac{1.5 x [tex] 10^{11} m}{3 x 10⁸ m/s} [/tex]

= 500 s

= 500/ 60

= 8.33 minutes

2) Distance = 1 mile = 63360 inches

Time taken = 8.92 min

= 8.92 x 60

= 535.2 s

Speed = \frac{distance}{time}

= \frac{63360 inches}{535.2 s}

= 118.39 in/ s

Distance = 1 mile = 63360 inches = 63360 x 2.54 cm = 63360 x 2.54 x 10^{-2} m

Time taken = 8.92 min

Speed = \frac{distance}{time}

= \frac{63360 x 2.54 x [tex] 10^{-2} m}{8.92 min} [/tex]

= 180.43 m/ min

1 m = 10⁻³ Km

1 min = 1/60 hour

1 m /min = 10⁻³ km/ \frac{1}{60 hour}

= 60/1000

=0.06 km/hr

180.43 m / min = 180 x 0.06 km / hr

= 10.93 km / hr

4 0
3 years ago
Relation between glancing and angle of deviation<br>​
shtirl [24]

Answer:

the Glancing angle is the angle between the incident ray and plane mirror which is 90o in the given case. The angle between the direction of the incident ray and the reflected ray is the angle of deviation. Since the angle of deviation for a plane mirror is twice the glancing angle, the angle of deviation is 1800.

5 0
2 years ago
Given the following equation: 2K + Cl2 -&gt; 2KCl How many grams of KCl is produced from 4.00 g of K and excess Cl2?
Thepotemich [5.8K]

Answer:

42.65g

Explanation:

Given parameters:

Mass of K = 4g

Unknown: Mass of KCl

Solution:

  Complete equation of the reaction:

              2K + Cl₂ → 2KCl

To solve this problem, we know that the reactant in short supply is potassium K and this dictates the amount of products that would be formed. The chlorine gas is in excess and we can't use it to determine the amount of product that would form.

Now, we work from the known to the unknown. Since we know the mass of K given in the reaction, we can simply find the molar relationship between the reacting potassium and the product. We simply convert the mass to mole and compare to the product. From there we can find the mass of KCl that would be produced.

Calculating number of moles of K

      Number of moles = \frac{mass}{molar mass}

        Number of moles of K =  \frac{4}{39} = 0.103mol

From the given reaction equation:

   2 moles of K will produce 2 moles of KCl

 Therefore 0.103mol of K will produce 0.103mol of KCl

To find the mass of KCl produced,

   Mass of KCl = number of moles of KCl x molar mass

Molar mass of KCl = 39 + 35.5 = 74.5gmol⁻¹

Mass of KCl = 0.103 x 74.5 = 42.65g

4 0
3 years ago
Read 2 more answers
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