3 MgCl2 + 2 Al = 3 Mg + 2 AlCl3
Since we know that we have 12 moles of MgCl2 and enough Al, we don't need to figure out the exact amount of Al.
3 MgCl2 / 2 AlCl3 = 12 mol MgCl2 / x mol AlCl2
cross-multiply
3 MgCl2(x mol AlCl2) = 12 mol MgCl2(2 AlCl3)
3x = 24
x=8
8 moles AlCl3
Alternatively, we know that we have 12 moles of MgCl2, and a coefficient of 3. This indicates a multiplier of 4 for the entire equation, meaning 2 AlCl3 multiplied by (4) = 8 moles
Answer:
Number of neutrons and stability
Explanation:
An isotope of an element is basically the same element but with different number of neutrons. For example here, boron can exist in the forms of boron-10 and boron-11, and so the latter would have one more neutron than the former one.
Adding an extra neutron may or may not disrupt the strong force that much, and so the half-life and stability of the new isotope can be slightly different than its most stable one.
The number of moles of oxygen in the gas is 1.5 L.
The correct option is (A).
<h3>What are moles? </h3>
The mole is the International System of Units' foundation unit of material quantity.
Given,
The volume of gas is 33.6 L
Pressure is 1 atm.
Temperature is 0°C
Molar gas volume is 22.4 L
There is no temperature and pressure is 1 atm.
By formula of moles, volume is divided by molar mass
Thus, option A is correct. 1.5 L.
Learn more about gas, here:
brainly.com/question/13123721
Answer:
20.67 kcal of energy is released.
Explanation:
It is given that, an exothermic reaction releases 86.5 kJ. We need to convet kJ to calories.
Since,
1 kcal = 4.184 kJ
So,
1 kJ = 0.239 kcal
For 86.5 kJ,
86.5 kJ = (0.239 × 86.5) kcal
86.5 kJ = 20.67 kcal
So, 20.67 kcal of energy is released.
In preparing diluted solutions from concentrated solutions we can use the following formula
c1v1 = c2v2
c1 and v1 are the concentration and volume of the concentrated solution respectively
c2 and v2 are the concentrations and volume of the diluted solution respectively
Substituting these values ,
20 mL x 1.0 M = C x 60 mL
C = 0.33 M
The concentration of the resulting diluted solutions is 0.33 M
