Question

State the oxidation number of S in }" alt="H_{2}SO_{3}" align="absmiddle" class="latex-formula">

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Answer 1

Taking into account the definition of oxidation number, the oxidation numbers of S in H₂SO₃ is 4.

Definition of oxidation number

The oxidation number is the charge that an atom has; is an integer that represents the number of electrons an atom puts into play when it forms a given compound.

In other words, the oxidation number of an element is a value that indicates the number of electrons that element gains or loses when it combines with another.

Oxidation number determination

To determine the oxidation state of different elements it is necessary to know that:

• The oxidation number of hydrogen in a compound is +1, except in metal hydrides, where is –1.
• The oxidation number of oxygen in a compound is –2, except in peroxides, where it is –1.

On the other side, the sum of the oxidation numbers of the existing elements in a chemical formula must add up to zero.

Then, considering the oxidation numbers of each element, multiplying it by the number of existing elements in the chemical formula and adding it and equaling it to zero, the value of the missing oxidation number can be obtained.

Oxidation numbers of S

In this case, the oxidation numbers of S in H₂SO₃ is calculated as:

2× (+1) + oxidation numbers of S + 3×(-2)= 0

2 + oxidation numbers of S -6= 0

oxidation numbers of S -4= 0

oxidation numbers of S= 4

Finally, the oxidation numbers of S in H₂SO₃ is 4.

Learn more about the oxidation number:

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Answer 2

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$\tt \bf Explanation:$

We start of by giving the oxidation number for hydrogen and oxygen, since we know these already.

So we have 2 hydrogen which each has a charge of +1 , and we have 3 oxygen which each has a charge of -2 If we cancel these out we would have that sulfur should have a charge of +4 to give a total charge of 0