Let me try:
Normal force= 169.74N
Coefficient of kinetic friction= 0.577
Explanation
a. For a given inclined plane, normal friction is equal to the force perpendicular to the plane which is equal to
mgcos theta = 20×9.8× cos30 = 169.74N
b. The coefficient of kinetic friction for an inclined plane is given as
tan theta =tan 30 = 0.577
Answer:
The value is 
Explanation:
From the question we are told that
The total time of flight is
Generally from kinematic equation

So v is the velocity at maximum height and the value is v = 0 m/s
So

=> 
Here u is the initial velocity of the dart as it leaves that gun
Gnerally the horizontal range of the dart is mathematically represented as

For maximum horizontal range the value of
So

=> 
The working equation to be used here is written below:
Q = kA(T₁ - T₂)/Δx
where
Q is the rate of heat transfer
k is the heat transfer coefficient
A is the cross-sectional area of the wall
T₁ - T₂ is the temperature difference between the sides of the wall
Δx is the thickness of the wall
The solution is as follows:
Q = (0.69 W/m²·°C)(5 m × 6 m)(50°C - 20°C)/(30 cm * 1 m/100 cm)
Q = 2,070 W/m
Newton’s Thrid Law, which states that for every reaction there is an opposite reaction.
The answer you’re looking for is
D. the frequency