1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
PolarNik [594]
3 years ago
11

A car travels forward with constant velocity. It goes over a small stone, which gets stuck in the groove of a tire. The initial

acceleration of the stone, as it leaves the surface of the road is,
a) vertically up
b) horizontally forward
c) horizontally backwards
d) zero
e) greater than zero but less than 45 degrees below the horizontal
Physics
1 answer:
kolbaska11 [484]3 years ago
8 0

Answer:

a) vertically up

Explanation:

A car travels forward with constant velocity. It goes over a small stone, which gets stuck in the groove of a tire. The initial acceleration of the stone, as it leaves the surface of the road is,

a) vertically up

b) horizontally forward

c) horizontally backwards

d) zero

e) greater than zero but less than 45 degrees below the horizontal

A vertically upward since that is the direction of centripetal acceleration at that time. as the stone enters the circular path of the tire, it does so with a centripetal acceleration which is directed upward

You might be interested in
In which of the following situation is work being done?
Afina-wow [57]

A wagon is pulled at an angle of 30 degrees to the horizontal.

6 0
3 years ago
What is the ability to complete extended periods of physical activity?
gogolik [260]
Endurance is the ability to complete extended periods of physical activity
8 0
3 years ago
Read 2 more answers
A 56 kg astronaut stands on a bathroom scale inside a rotating circular space station. The radius of the space station is 250 m.
Zielflug [23.3K]

Answer:

The speed of space station floor is 49.49 m/s.

Explanation:

Given that,

Mass of astronaut = 56 kg

Radius = 250 m

We need to calculate the speed of space station floor

Using centripetal force and newton's second law

F=mg

\dfrac{mv^2}{r}=mg

\dfrac{v^2}{r}=g

v=\sqrt{rg}

Where, v = speed of space station floor

r = radius

g = acceleration due to gravity

Put the value into the formula

v=\sqrt{250\times9.8}

v=49.49\ m/s

Hence, The speed of space station floor is 49.49 m/s.

6 0
3 years ago
You throw a glove straight upward to celebrate a victory. Its initial kinetic energy is K and it reaches a maximum height h. Wha
Rasek [7]

Answer:

K/2

Explanation:

The law of conservation of mechanical energy states that the sum of the kinetic and potential energies is a constant at any point.

At maximum height, the glove has purely potential energy but at the bottom, it has purely kinetic energy.

The potential energy at the top = kinetic energy at the bottom. The potential energy is given by

PE = mgh

At half height, this potential energy is

PE = \frac{1}{2}mgh

At this height, PE + KE = Constant = KE at bottom or PE at maximum height.

mgh = \frac{1}{2}mgh +KE

KE = \frac{1}{2}mgh = K/2

5 0
3 years ago
A high diver of mass 51.7 kg steps off a board 10.0 m above the water and falls vertical to the water, starting from rest. If he
zmey [24]

Answer:

851.33 N

Explanation:

Using newton;s equation of motion,

v² = u² + 2gh ......... Equation 1

Where v = final velocity, u = initial velocity, g = acceleration due to gravity, h = height

Given: u = 0 m/s(from rest), h = 10 m g = 9.8 m/s².

Substitute into equation 1

v² = 0² + 2(9.8)(10)

v² = 196

v = √196

v = 14 m/s.

Note: As the Diver touches the water,  u = 14 m/s and v = 0 m/s( stopped)

Using,

d = (v+u)t/2 .............. equation 2

Where d = distance moved by the diver in water before its motion stopped, t = time taken before it comes to rest

Given: v = 0 m/s, u = 14 m/s t = 2.10 s

Substitute into equation 2

d = (0+14)2.1/2

d = 14.7 m.

Finally

work done by the water to stop the diver = potential energy of the diver

F×d = mgh'................Equation 3

Where F = force of the diver in water, d = distance of the diver in the water, m = mass of the diver, g = acceleration due to gravity, h' = height of the diver from the point of fall to the point where he comes to rest

making F the subject of the equation,

F = mgh/d ............ Equation 4

Given: m = 51.7 kg, h = 10 m, g = 9.8 m/s², d = 14.7 m.

Substitute into equation 4

F = 51.7(10+14.7)(9.8)/14.7

F = 851.33 N

Hence the upward force the water exert on her = 851.33 N

8 0
3 years ago
Other questions:
  • Rutherford proposed that
    13·1 answer
  • If you were to drop an egg on concrete would it crack it
    6·2 answers
  • A person has long hair hanging straight down from their head. A second person rubs a balloon with felt so that the balloon is ne
    7·1 answer
  • 5. A race car has a mass of 710 kg. It starts from rest and travels 40.0m in 3.0s. The car is uniformly accelerated during the e
    7·1 answer
  • 8. A car travels at a constant velocity of 70 mph for one hour. By the end of the second hour, the car’s velocity was 60 mph. At
    10·1 answer
  • A sheet of red paper will look black when illuminated with
    13·2 answers
  • A mass is undergoing simple harmonic motion. When its displacement is 0, it is at its equilibrium position. At that moment, its
    5·2 answers
  • (4)science who ever gets this right will get a brainlest
    5·2 answers
  • How is it that even light precipitation can still cause the collection of large amounts of water.
    12·1 answer
  • if an object moves from a position of x = 12 m to x = 124 m, then back to x = 98 m. If the time it takes to complete this motion
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!