Answer:
Flying in a plane gives the notion of one exiting the earths atmosphere and also, there is the risk of exposure to dangerous cosmic radiation.
Nuclear power plants possesses great forms of chemicals and toxic elements that could lead to chemical radiation and further more, cause mutation of human cells which invariably brings cancer. There is the extreme health hazard to be weary of when in a nuclear power plant.
Being struck by lightning can be hazardous to ones health and could bring forth a number of health problems like; hearing and/or vision loss, irregular heartbeat, headache, chest pain, hypersomnia, confusion, shortness of breath, weakness, stiffness, and/or temporary paralysis.
Exposure to BPA in plastics has been connected to be cause of a number of fertility problems, male impotence, heart disease, and other conditions.
What do all of these problems have in common? They all are things you never see coming, you can't literally control the particles from nuclear plants, the forces handling the elevation and descending of planes, the chemical and physical nature of compounds involved in lightning production as compared to not exercising and knowing what could come from that. The side effects of not exercising can not be compared to the latter explained and those are life threatening processes.
Answer- I would think low
Answer:
22Volts
Explanation:
The pd at the terminal is known as the emf
Since there are Ten 2.2V cells
Terminal voltage = number of cells * pd of one cell
Terminal voltage = 10 * 2.2
Terminal voltage = 22V
Hence the pd at the battery terminals is 22Volts
Explanation:
The temperature must be hot enough to allow the ions of deuterium and tritium to have enough kinetic energy to overcome the Coulomb barrier and fuse together. The ions must be confined with a high ion density to achieve a suitable fusion reaction rate.
Answer:
609547.12 Pa ≈ 6.10×10^5 Pa
Explanation:
Step 1:
Data obtained from the question. This include the following:
Force (F) = 49.8 N
Radius (r) = 0.00510 m
Pressure (P) =..?
Step 2:
Determination of the area of the head of the nail.
The head of a nail is circular in nature. Therefore, the area is given by:
Area (A) = πr²
With the above formula we can obtain the area as follow:
Radius (r) = 0.00510 m
Area (A) =?
A = πr²
A = π x (0.00510)²
A = 8.17×10^-5 m²
Therefore the area of the head of the nail is 8.17×10^-5 m²
Step 3:
Determination of the pressure exerted by the hammer.
This is illustrated below:
Force (F) = 49.8 N
Area (A) = 8.17×10^-5 m²
Pressure (P) =..?
Pressure (P) = Force (F) /Area (A)
P = F/A
P = 49.8/8.17×10^-5
P = 609547.12 N/m²
Now, we shall convert 609547.12 N/m² to Pa.
1 N/m² = 1 Pa
Therefore, 609547.12 N/m² = 609547.12 Pa.
Therefore, the pressure exerted by the hammer on the nail is 609547.12 Pa or 6.10×10^5 Pa
