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just olya [345]
3 years ago
12

A man weighs 1190 n on earth. what would he weigh on jupiter, where the free-fall acceleration is 25.9 m/s 2 ? the acceleration

of gravity is 9.8 m/s 2 . answer in units of n.
Physics
1 answer:
Elden [556K]3 years ago
8 0
The answer would be 3,145N. Using W=mg solve for the mass of the man on earth. Once you have the mass you can multiply it by the gravity of Jupiter giving you his weight in Newton’s on Jupiter.
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The actual mechanical advantage of any machine is its__________divided by its________________
zaharov [31]

Answer: Load divided by it effort

Explanation:

Mechanical advantage of any machine is its load divided by its effort

4 0
3 years ago
Which of these best defines weather? (3 points) a Atmospheric conditions over 30-year period Ob Day-to-day condition of the atmo
prisoha [69]

Answer:

b Day-to-day condition of the atmosphere

Explanation:

Weather is short term, Climate is long term

3 0
2 years ago
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What is the kinetic energy of an object that has a mass of 12 kg and moves with a velocity of 10 m/s
WITCHER [35]

Answer:

600 J

Explanation:

The formula to find the kinetic energy of an object is \frac{1}{2}mV^2

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  • V = velocity in m/s
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Now, let's plug in the variables we're given and simplify.

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6 0
2 years ago
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A rollercoaster car has 2500 J of potential energy and 160 J of
lara31 [8.8K]

Answer:

E_{k2}=2660 [J] kinetic energy.

Explanation:

The energy in the initial state i.e. when the rollercoaster is at the top is equal to the energy in the final state i.e. when it is at the bottom of the hill.

These states can be represented by means of the second equation.

E_{k1}+E_{p1}=E_{k2}\\160 + 2500 = E_{k2}\\E_{k2}=2660 [J]

Since the rollercoaster is located in the bottom of the hill where the potential energy level is zero, therefore there is only kinetic energy in the second state.

8 0
2 years ago
Use the drop-down menus to complete the statement.
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Resistance is equal to relation between voltage and current.

R = \frac{U}{I}

If we express current:

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So the answer should be C voltage and B zero.

Hope this helps!
8 0
3 years ago
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