V = frequency * wavelength
v = 80 * 4
v = 320m/s
Answer:
Check below for the explanation
Explanation:
Since it is stated that the ring is dropped from a height, h, through a non uniform magnetic field, two kinds of force will act on the ring, namely:
- A magnetic force (that is non uniform since the field is non uniform)
- Gravitational force
A certain amount of torque is provided by the non uniform magnetic force on the ring while the force gravity pulls it down. Due to the downward pull by the force of gravity on the ring and the torque acting on it as a result of the non uniform magnetic force, the ring begins to rotate.
Answer:
D. 2.5 m
Explanation:
1.5 m up to the beam + 0.5 m up + 0.5 m down = 2.5 m total
Answer: By 47
Explanation: subtract 310 and 263
<span>To find the gravitational potential energy of an object, we can use this equation:
GPE = mgh
m is the mass of the object in kg
g = 9.80 m/s^2
h is the height of the object in meters
GPE = mgh
GPE = (0.700 kg) (9.80 m/s^2) (1.5 m)
GPE = 10.3 J
The gravitational potential energy of this can is 10.3 J</span>
