I am only a HS Freshman so I might be wrong
Answer:
3. Its potential energy and the formula for PE = mgh so you would use the weight given (Weight = mg) and mg is in the (Potential Energy) forumula so we multiply 3 by 30 and get 90 Joules
4. We would do the same thing with this: PE = mgh; PE = 10*3 = 30 Joules
Once again I am only a Freshman and I have taken Private AP Physics classes so just maybe wait for someone who is more confident.
This is just what I would answer
btw, for problem 5, the fromula for kinetic energy is 1/2*m*v^2
Answer:
Rita runs faster
Explanation:
To obtain the answer to the question given, we determine the speed of Rita. This can be obtained as follow:
Distance = 1.6 km
Time = 15 mins
Speed =?
Next, we shall convert 15 mins to hour. This can be obtained as follow:
60 mins = 1 h
Therefore,
15 mins = 15 mins × 1 h / 60 mins
15 mins = 0.25 h
Thus, 15 mins is equivalent to 0.25 h.
Finally, we shall determine speed of Rita as follow:
Distance = 1.6 km
Time = 0.25 h
Speed =?
Speed = distance / time
Speed = 1.6 / 0.25
Speed = 6.4 Km/h
Thus Rita's speed is 6.4 Km/h
Comparing the speed of Rahul and Rita
Rahul's speed = 4.5 km/h
Rita's speed = 6.4 Km/h
We can see that Rita's speed is greater than Rahul's speed. This simply indicates that Rita runs faster than Rahul.
Complete Question
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is 
The value for static friction is 
Explanation:
From the question we are told that
The mass of the clock is 
The first horizontal force is 
The second horizontal force is 
Generally the static frictional force is equal to the first horizontal force
So
=> 
=>
Generally the kinetic frictional force is equal to the second horizontal force
So
Answer:
parallel circuit
Explanation:
In a parallel circuit, the potential difference across each of the resistors that make up the circuit is the same. This leads to a higher current flowing through each resistor and subsequently the total current flowing through all the resistors is higher.
