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Gemiola [76]
3 years ago
6

Odtake them for freee​

Physics
2 answers:
VARVARA [1.3K]3 years ago
8 0

Answer:

Can i plz have brainliest

Explanation:

Stolb23 [73]3 years ago
5 0

Answer:

Thank youu89okkiiiooo

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A transformer connected to a 110–(V) (rms) ac line is to supply 10.0 (V) (rms) to a portable electronic device. The load resista
spayn [35]

Answer:

Explanation:

a ) V( primary ) = 100 V

V( secondary ) = 10 V

No of turns ( secondary ) / No of turns ( primary ) = 10 / 100

= 1 / 10

b ) current in secondary

= volt ( secondary ) / resistance

= 10 /6 = 1.67 A

c )

Average power to secondary

= V  ( secondary ) x current ( secondary )

= 10 x 10 / 6

= 16.67 W

d )

Power in primary = power in secondary = 16.67 W

e ) current drawn by ac line ( primary )

Volt ( primary ) x current ( primary ) = power in primary

= 16.67

current ( primary )

= 16.67 / 100

= 0.167 A

5 0
3 years ago
A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
tensa zangetsu [6.8K]

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4       ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28   momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

5 0
2 years ago
A sound wave has a frequency of 250 Hz and a wavelength of 2.5 m. What is the speed of the wave?
Digiron [165]

ANSWER

625 m/s

EXPLANATION

Given:

• The frequency of the sound wave, f = 250 Hz

,

• The wavelength, λ = 2.5 m

Find:

• The speed of the wave, v

The speed of a wave of wavelength λ and frequency f is given by,

v=f\cdot\lambda

Substitute the known values and solve,

v=250Hz\cdot2.5m=625m/s

Hence, the speed of the wave is 625 m/s.

3 0
1 year ago
What is a galaxies ???
-Dominant- [34]

Answer:

A galaxy is a gravitationally bound system of stars, stellar remnants, interstellar gas, dust, and dark matter. The word galaxy is derived from the Greek galaxias, literally "milky", a reference to the Milky Way.

Explanation:

4 0
3 years ago
Read 2 more answers
Ted Clubber Lang. A hook in boxing primarily involves horizontal flexion of the shoulder while maintaining a constant angle at t
il63 [147K]

Answer:

15 m/s or 1500 cm/s

Explanation:

Given that

Speed of the shoulder, v(h) = 75 cm/s = 0.75 m/s

Distance moved during the hook, d(h) = 5 cm = 0.05 m

Distance moved by the fist, d(f) = 100 cm = 1 m

Average speed of the fist during the hook, v(f) = ? cm/s = m/s

This can be solved by a very simple relation.

d(f) / d(h) = v(f) / v(h)

v(f) = [d(f) * v(h)] / d(h)

v(f) = (1 * 0.75) / 0.05

v(f) = 0.75 / 0.05

v(f) = 15 m/s

Therefore, the average speed of the fist during the hook is 15 m/s or 1500 cm/s

6 0
3 years ago
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