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sveticcg [70]
4 years ago
6

What is an example of electrons moving?

Physics
1 answer:
alexgriva [62]4 years ago
7 0
C . because if you do it phisical you can see that it works

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Two objects attract each other gravitationally with a force of 2.5 x 10^-10N when they are 0.25 m apart. Their total mass is 4.0
In-s [12.5K]

Answer:

M = 3.9406 kg and m = 0.0594 kg

Explanation:

The gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them. Mathematically it is expressed as follows:

Fg = (G×M×m)/r²    Formula (1)

Where:

Fg is the gravitational force (N)

G is the universal gravitation constant, G = 6.67 × 10⁻¹¹ (N×m²)/kg²

M and m are the masses of the bodies that interact  (kg).

r is the distance that separates them (m).

Known Data

Fg = 2.5 × 10⁻¹⁰ N

r = 0.25 m

G = 6.67 × 10⁻¹¹ (N×m²)/kg²

Problem development

We propose 2 equations

M + m = 4kg

M = 4 - m equation (1)

We replace in formula (1)

2.5 × 10⁻¹⁰ = (6.67 × 10⁻¹¹ × M × m)/(0.25)²

2.5 × 10⁻¹⁰ × (0.25)² = (6.67 × 10⁻¹¹ × M × m)

(2.5 × 10⁻¹⁰ × (0.25)²)/(6.67 × 10⁻¹¹) = M × m

M × m = 0.234 equation (2)

We replace M = 4 - m in equation (2)

(4 - m) × m = 0.234

4m - m² = 0.234

m² - 4m + 0.234 = 0 (quadratic equation)

We apply the formula for the quadratic equation and obtain 2 values for m that meet the conditions:

m = 3.9406 kg or m =  0.0594 kg

We replace m in equation (1)

M = 4 - 3.9406 = 0.0594 kg or M = 4 - 0.0594 = 3.9406

To meet the condition that M + m must give 4 kg, one mass must be equal 3.9406 and the other must equal 0.0594, then:

M = 3.9406 kg and m = 0.0594 kg

6 0
4 years ago
School homework about multiplying fractions <br><br>worth 30 brainly points​
RoseWind [281]

Answer:

Explanation:

1. \frac{1}{3} x \frac{6}{7} = \frac{6}{21}

          = \frac{2}{7}

b. \frac{6}{8} + \frac{4}{9} = \frac{24}{72}

            = \frac{1}{3}

c. \frac{10}{15} x \frac{3}{4} = \frac{30}{60}

            = \frac{1}{2}

d. \frac{7}{10} of \frac{5}{10} = \frac{7}{10} x \frac{5}{10}

                = \frac{35}{100}

                = \frac{7}{20}

e. \frac{3}{8} of \frac{4}{6} = \frac{3}{8} x \frac{4}{6}

            = \frac{12}{48}

            = \frac{1}{4}

f. \frac{7}{12} of \frac{9}{14} = \frac{7}{12} x \frac{9}{14}

              = \frac{63}{168}

              = \frac{3}{8}

2. \frac{22}{6} x \frac{3}{11} = \frac{66}{66}

              = 1

b. \frac{15}{6} x \frac{4}{5} = \frac{60}{30}

             = 2

c. \frac{25}{8} x \frac{4}{10} = \frac{100}{80}

              = \frac{5}{4}

d. \frac{33}{12} x \frac{4}{15} = \frac{132}{180}

             = \frac{11}{15}

4 0
3 years ago
A 12 v automobile battery is connected to an electric starter motor. the current through the motor is 206
vampirchik [111]
Power = (voltage) x (current). The motor consumes (12)x(206)=2,472 watts. Some of it is dissipated as heat, but most of it is used to do useful work by turning the engine over to make it start.
5 0
3 years ago
(Don't answer unless you know a lot about tf2 cod, and etc. Ty)
aev [14]
What about cod my guy which one are we talking ?
7 0
3 years ago
Will Upvote!!!
katrin2010 [14]
The answer is A. Since the car is moving at a constant velocity, the car not accelerate no matter how far it travels.
5 0
3 years ago
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