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Margaret [11]
3 years ago
14

In a follow-up experiment, two identical gurneys are placed side-by-side on a ramp with their wheels locked to eliminate spinnin

g. Gurney 1 has a dummy placed on it to give it a total mass of 200 kg, while Gurney 2 is loaded with a dummy that makes it only 50 kg overall. If the ramp has a coefficient of friction of μs, which gurney is more likely to slide down the ramp?
Physics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

Gurney 2 is more likely to slide.

Explanation:

We know static friction force is equal to the mass of the object times coefficient of friction.

Static friction force is the frictional force applied to the object which prevents the body to slip or slide when the body is at rest.

Now in the question, the gurney 1 which is placed in the ramp has a total mass of 200 kg and the coefficient of friction between the ramp and the gurney is μ.

And the gurney 2 place on the same ramp has a total mass of 50 kg and coefficient of friction μ between the ramp and the gurney 2.

Both the gurneys are at rest initially, means they are acted upon by static frictional force.

Mathematically, Static friction force = mass x coefficient of friction

So static friction depends on mass and since it is clear that the gurney 1 has a greater mass of 200 kg than the gurney 2 which has a total of 50 kg.

Therefore gurney 1 has greater static friction that is acted upon it which restricts it to slide or slip.

So, gurney 2 is more likely to slide down the ramp.

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nadezda [96]

Answer:

2m/s^2

Explanation:

Clculate the acceleration:

V = u +at

20m/s = 0 + a*10s

a = 20m//10s

a = 2m/s²

From the data given , it is not possible to calculate the displacement , because no direction of motion is given

But it is possible to calculate the distance travelled

Distance = ut + ½ *a*t²

distance = 0 + ½ * 2m/s * 10²s

distance = 100m

6 0
3 years ago
What phase are daughter cells in as a result of mitosis
NemiM [27]
They are in interphase
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4 years ago
A projectile is fired at an upward angle of 45.0º from the top of a 265-m cliff with a speed of .sm 185 What will be its speed w
nignag [31]

The final velocity of the projectile when it strikes the ground below is 198.51 m/s.

<h3>Time of motion of the projectile</h3>

The time taken for the projectile to fall to the ground is calculated as follows;

h = vt + ¹/₂gt²

where;

  • h is height of the cliff
  • v is velocity
  • t is time of motion

265 = (185 x sin45)t + (0.5)(9.8)t²

265 = 130.8t + 4.9t²

4.9t² + 130.8t - 265 = 0

solve the quadratic equation using formula method,

t = 1.89 s

<h3>Final velocity of the projectile</h3>

vyf = vyi + gt

where;

  • vyf is the final vertical velocity
  • vyi is initial vertical velocity

vyf = (185 x sin45) + (9.8 x 1.89)

vyf = 149.322 m/s

vxf = vxi

where;

  • vxf is the final horizontal velocity
  • vxi is the initial horizontal velocity

vxf = 185 x cos(45)

vxf = 130.8 m/s

vf = √(vyf² + vxf²)

where;

  • vf is the speed of the projectile when it strikes the ground below

vf = √(149.322²  +  130.8²)

vf = 198.51 m/s

Learn more about final velocity here: brainly.com/question/6504879

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3 years ago
If a current of 2. 4 a is flowing in a wire of diameter 2. 0 mm, what is the average current density?
HACTEHA [7]

The average current density is 7.6 × 10⁵ A/m².

To calculate the current density current will be 2.4 A.

Diameter of a wire = 2mm.

The cross-sectional area of the wire is given by r = d/2

where r is the radius of the wire.  

Then, the cross-sectional area is = 0.00000314159265

                                                                   = 3.1 × 10⁻⁶ m².

<h3>What is average current density?</h3>

         Consider a current carrying conductor, the current density depends upon  the current flow in the conductor. If the current flow in the conductor will be high then the current density will also be high. Using the average current flowing through the conductor, the average current density will be found.

Average current density j = I / A Ampere/ meter².

By substituting the values in the formula,

             j = 2.4 / ( 3.1 × 10⁻⁶)

               = 7.6 × 10⁵ A/m².

Hence, the current density can be calculated.

Learn more about average current density,

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Use the accompanying seismogram to answer which of the three types of seismic waves reached the seismograph first.
UkoKoshka [18]

Answer:

Primary waves (P-waves)

Explanation:

Due to excess of the energy inside the earth when the tectonic plates begin to slide or fracture then the energy is released in the form of seismic waves, this causes the earthquake.

<u>Two types of seismic waves are generally responsible for the earth quakes:</u>

  1. body waves
  2. surface waves

Body waves are of two types:

Primary waves (P-waves)

These are the fastest of all the waves involved in the earth-quake which travel at a speed of 1.6 km to 8 km per second.

They can pass trough solids, liquids and gases. They arrive at the surface as an instant thud.

Secondary waves (S-waves)

They can only pass through the solids and they move slower than the P-waves.

As S-waves move, they displace the rock particles, pushing them outwards perpendicular to the wave-path that leads to the earthquake-related first rolling period.

Surface waves (L-waves/ long waves)

  • These waves move along the surface of the earth. They are responsible for the earthquake's carnage.
  • They move up and down the Earth's surface, rocking the foundations of man-made structures.
  • Surface waves are slowest of the three waves, which means that they are the last to arrive. So at the end of an earthquake usually comes the most powerful shaking.
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3 years ago
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