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S_A_V [24]
3 years ago
14

4. What is the difference between an open system and a closed system?

Chemistry
1 answer:
Nimfa-mama [501]3 years ago
5 0

Systems can exist in three ways as open systems, closed systems, and isolated systems. The main difference between open and closed system is that in an open system, matter can be exchanged with the surrounding whereas, in a closed system, matter cannot be exchanged with the surrounding.

btw why not just look it up on google? btw btw brainliest plz

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A student determines the volume of a cube to be 4.6 cm?
pav-90 [236]

Answer:

6.98%

Explanation:

% error= |experimental value - actual value|/actual value × 100

Experimental value= 4.6 cm

Actual value= 4.3 cm

% error = |4.6-4.3|/4.3 × 100

% error = 6.98%

6 0
3 years ago
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How many significant digits are there in the number 204.0920?
mihalych1998 [28]
204.0920-It have 7 significant digits
6 0
4 years ago
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What volume of ethanol (density = 0.7893 g/cm3) should be added to 450. ml of water in order to have a solution that freezes at
AysviL [449]
According to this formula :
ΔTf= i Kf m
i is van't Hoff factor= 1
Kf = 1.86 
m the molality we need to assume it 
m= x moles of C2H5OH / Kg of mass 
∴ 15 = 1 * 1.86 * ( x moles of C2H5OH/ 0.45 kg)
∴X = 3.629 moles 
mass = no.of moles x molar mass of C2H5OH
          = 3.629 X 46 = 167 g 
∴the volume = mass / denisty
                      = 167 / 0.7893 = 211.57≈ 212 mL

4 0
4 years ago
Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?
fiasKO [112]
<span>carbon + oxygen → carbon dioxide</span>
3 0
3 years ago
The amount of heat absorbed by the alcohol was determined to be 1.17kJ. Given that the specific heat of the alcohol is 2.42J/gC
quester [9]

Answer:

                      ΔT  =  20.06 °C

Explanation:

The equation used for this problem is as follow,

                                    Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  1.17 kJ = 1170 J

           m  =  mass  =  24.1 g

           Cp  =  Specific Heat Capacity  =  2.42 J.g⁻¹.°C⁻¹

           ΔT  =  Change in Temperature  =  <u>??</u>

Solving eq. 1 for ΔT,

                                ΔT  =  Q / m Cp

Putting values,

                                ΔT  =  1170 J / 24.1 g × 2.42 J.g⁻¹.°C⁻¹

                                ΔT  =  20.06 °C

6 0
3 years ago
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