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Answer:
First Part: branched chain, cycloalkane, straight chain
Second Part: straight chain, branched chain, cycloalkane.
Explanation:
Edg 2021
Answer:
18.0 Ampere is the size of electric current that must flow.
Explanation:
Moles of electron , n = 550 mmol = 0.550 mol
1 mmol = 0.001 mol
Number of electrons = N

Charge on N electrons : Q

Duration of time charge allowed to pass = T = 49.0 min = 49.0 × 60 seconds
1 min = 60 seconds
Size of current : I



18.0 Ampere is the size of electric current that must flow.
Answer:
wax i think
Explanation:
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