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4vir4ik [10]
3 years ago
13

I’ve gotten the answer as x=.478 but when plugging back in, .46/.478 ≠ .22. Help please

Chemistry
1 answer:
ivanzaharov [21]3 years ago
6 0

Answer:

15. 2.66 moles .

16. 2.09L.

Explanation:

Molarity of a solution is simply defined as the mole of solute per unit litre of the solvent. Mathematically, it is represented as:

Molarity = mole /Volume.

With the above formula, let us answer the questions given above

15. Data obtained from the question include the following:

Volume of solution = 1.4L

Molarity = 1.9M

Mole of solute =.?

Molarity = mole /Volume

1.9 = mole / 1.4

Cross multiply

Mole = 1.9 x 1.4

Mole = 2.66 moles

Therefore, the mole of the solute present in the solution is 2.66 moles.

16. Data obtained from the question include the following:

Mole of solute = 0.46 mole

Molarity = 0.22M

Volume of solvent (water) =.?

Molarity = mole /Volume

0.22 = 0.46/Volume

Cross multiply

0.22 x Volume = 0.46

Divide both side 0.22

Volume = 0.46/0.22

Volume = 2.09L

Therefore, 2.09L of water is required.

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The density of the object is 0.467 36 g/cm³.

The mass of the object is 389.27 g.

The volume of the object is 832.92 cm³.

Density = mass/volume = 389.27 g/832.92 cm³ = 0.467 36 g/cm³

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What is the balanced equation for the combustion of sulfur
Alex17521 [72]

Answer:

There are three possible chemical equations for the combustion of sulfur:

  • 2S (s)  + O₂ (g)  → 2SO (g)

  • S (s) + O₂ (g) → SO₂ (g)

  • 2S (s) + 3O₂ (g) → 2SO₃ (g)

Explanation:

<em>Combustion</em> is a reaction with oxygen. The products of the reaction are oxides, and energy is released in the form of heat and light.

<em>Sulfur</em> iis a nonmetal, so the oxide formed is a nonmetal oxide.

The most common oxidation numbers of sulfur are -2, + 2, + 4, and + 6.

The combination of sulfur with oxygen may be only with the positive oxidation numbers (+2, + 4, and +6).

Then you have three different equations for sulfur combustion:

<u>1) Oxidation number +2:</u>

  • S(s) + O₂(g) → SO(g)

Which when balanced is: 2S(g) + O₂(g) → 2SO(g)

<u>2) Oxitation number +4:</u>

  • S(s) + O₂(g) → SO₂(g)

That equation is already balanced.

<u>3) Oxidation number +6:</u>

  • S(s) + O₂(g) → SO₃(g)

Which when balanced is: 2S(s) + 3O₂(g) → 2SO₃(g)

3 0
4 years ago
A mixture of 10 moles of A, 5 moles of B and 15 moles of C is placed in a one liter container at a constant temperature. The rea
Cloud [144]

Answer:

Equilibrium constant is 0.0873

Explanation:

For the reaction:

A + B ⇄ C

Equilibrium constant is defined as:

K = [C] / [A] [B]

concentrations in equilibrium of each reactant are:

[A] = 10 - X

[B] = 5 - X

[C] = 15 + X

If concentration in equilibrium of B is 9, X is:

[B] = 5 - X = 9 → <em>X = -4 </em>

Replacing:

[A] = 10 - (-4) = 14

[B] = 5 - (-4) = 9

[C] = 15 + (-4) = 11

K = 11 / (14×9) = 0.0873

Thus, <em>equilibrium constant is 0.0873</em>

3 0
3 years ago
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