All categories

3 years ago

Define momentum in term of mass and velocity

Physics

1 answer:

KengaRu [80]3 years ago

5 0

Answer:

Momentum: It is the quantity of motion of a moving body, measured as a product of its Mass and Velocity.

Explanation:

Definition of momentum :

Momentum is the quantity of motion of a moving body, measured as a product of its Mass and Velocity.

Momentum is denoted by p
Formula for momentum is
$p = mass\times velocity$

Its unit is kg-m/s.

For example:

A bowling ball of large mass moving very slowly can have the same momentum as a cricket ball of small mass that is thrown with a very high velocity

You might be interested in

Vector of magnitude 15 is added to a vector of magnitude 25. The magnitude of this sum

loris [4]

Explanation:

Given that,

Magnitude of vector A, |A| = 15

Magnitude of vector B, |B| = 25

We need to find the magnitude of this sum.

The maximum sum of the resultant vector,

$R_{max}=|A_1|+|A_2|\\\\=15+25\\\\=45$

The minimum sum of the resultant vector,

$R_{min}=|A_1|-|A_2|\\\\=15-25\\\\=-10$

So, the magnitude of this sum either 45 or -10.

6 0

2 years ago

Having a stronger negative or positive change on one side is called what ?

maxonik [38]

Do you have choices?

5 0

2 years ago

Um ladrão tenta fugir sozinho carregando em suas mãos uma mala cheia de barras de ouro. A densidade do ouro é igual a 20 g/cm³,

Roman55 [17]

I believe the answer to your question is A

4 0

3 years ago

When the mass is removed, the length of the cable is found to be l0 = 4.66 m. After the mass is added, the length is remeasured

zaharov [31]

Answer:

$\gamma=6.07*10^5\frac{N}{m^2}$

Explanation:

For a linear elastic material Young's modulus is a constant that is given by:

$\gamma=\frac{F/A}{\Delta L/L_0}$

Here, F is the force exerted on an object under tensio, A is the area of the cross-section perpendicular to the applied force, $\Delta L$ is the amount by which the length of the object changes and $L_0$ is the original length of the object. In this case the force is the weight of the mass:

$F=mg\\F=55kg(9.8\frac{m}{s^2})\\F=539N$

Replacing the given values in Young's modulus formula:

$\gamma=\frac{F/\pi r^2}{(L_1-L_0)/L_0}\\\gamma=\frac{539N/\pi(0.045m)^2}{(5.31m-4.66m)/4.66m}\\\gamma=6.07*10^5\frac{N}{m^2}$

6 0

2 years ago

A car takes off from rest takes of from rest and covers a distance of 80m on a straight road in 10s.Calculate the magnitude of i

hodyreva [135]

Initial velocity (u) = 0 m/s [the car was at rest]
Distance (s) = 80 m
Time (t) = 10 s
Let the magnitude of acceleration be a.
By using the equation of motion, $s = ut + \frac{1}{2} a {t}^{2}$ we get, $80 = 0 \times 10 + \frac{1}{2} \times a \times {10}^{2} \\ = > 80 = \frac{1}{2} \times 100a \\ = > 80 = 50a \\ = > a = \frac{80}{50} \\ = > a = 1.6$

Answer:

The magnitude of its acceleration is 1.6 m/s^2.

Hope you could get an idea from here.

Doubt clarification - use comment section.

4 0

2 years ago

Define momentum in term of mass and velocity​

Define momentum in term of mass and velocity