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3 years ago

Which statement is true?

Physics

1 answer:

vivado [14]3 years ago

4 0

Answer:

The speed of sound in air is not affected by the temperature

Explanation:

It just isn't™

You might be interested in

What is the average speed of an object that travels 50 meters in 2 seconds? Select one: a. 100 m/s b. 25 m/s c. 50 m/s d. 2 m/s

AURORKA [14]

Answer:

Average speed, v = 25 m/s

Explanation:

It is given that,

Distance travelled by the object, d = 50 meters

Time taken, t = 2 seconds

Average speed is defined as the total distance divided by total time taken i.e.

$v=\dfrac{d}{t}$

$v=\dfrac{50\ m}{2\ s}$

v = 25 m/s

So, the sped of the object is 25 m/s. Hence, this is the required solution.

8 0

3 years ago

How can the distance between the first bright band and the central band be increased in a double-slit experiment?

Strike441 [17]

Answer:

Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.

Explanation:

The distance $y$ from the central band to the first bright band is given by

$y = \dfrac{ \lambda D}{d}$

where $\lambda$ is the wavelength of light (or any particle), $D$ is the distance to the screen, and $d$ is the slit separation.

From this equation we see that, by increasing the wavelength $\lambda$ , increasing the distance from the screen $D$ , and decreasing the slit separation $d$ , we increase the distance between the first bright band and the central band.

Therefore, the 2nd choice "<em>Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.</em>" is correct.

8 0

4 years ago

You are in a car travelling to dinner when a light ahead suddenly turns red.

mamaluj [8]

Answer:

The car needs nearly 2.6 s

8 0

4 years ago

You illuminate a slit with a width of 71.7 μm with a light of wavelength 737 nm and observe the resulting diffraction pattern on

miskamm [114]

To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,

$sin(\theta_{min}) = \frac{m\lambda}{D}$

Here,

m = Order of the fringes

D = Distance between slits

$\lambda$ = Wavelength

Replacing with our values we have,

$sin(\theta_{min}) = \frac{(1)(737*10^{-9})}{71.7*10^{-6}m}$

$sin(\theta_{min}) = 0.01028$

Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then

$Y=Lsin\theta$