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emmasim [6.3K]
3 years ago
9

Anna needs to move a box of paperback books across the room. If she applies a force of 20 newtons to the box, what is the magnit

ude of the force exerted by the box on Anna?
Physics
2 answers:
vlabodo [156]3 years ago
5 0
Newton's third law tells us that for every force there is an equal and opposite force.  This means that if Anna exerts a force of 20 Newtons on the box, the box exerts a force of 20 Newtons on Anna.
ycow [4]3 years ago
3 0

Answer:

The magnitude of the force exerted by the box on Anna is 20 newtons.

Explanation:

It is given that, Anna needs to move a box of paperback books across the room. If she applies a force of 20 newtons to the box. We need to find the magnitude of the force exerted by the box on Anna.

The force exerted by the box on Anna is 20 newtons but it acts in the opposite direction as per Newton's third law of motion. The third law of motion explains the impact of forces i.e. action and reaction force.

So, the magnitude of the force exerted by the box on Anna is also 20 newtons. Hence, this is the required solution.

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A circuit is built based on this circuit diagram. What is the equivalent resistance of the circuit?
Dmitry_Shevchenko [17]
The three resistors are connected to the same points of the circuit, so they are in parallel configuration. The equivalent resistance of 3 resistors in parallel is given by:
\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}+ \frac{1}{R_3}
If we plug the values of the resistances into the formula, we find
\frac{1}{R_{eq}}= \frac{1}{3.0 \Omega}+ \frac{1}{6.0 \Omega}+ \frac{1}{9.0 \Omega}= \frac{6+3+2}{18.0 \Omega} = \frac{11}{18.0 \Omega}
From which we find the equivalent resistance:
R_{eq} =  \frac{18.0}{11} \Omega =1.6 \Omega

So, the correct answer is B.
7 0
2 years ago
As you are cycling to the Q center one spring day, you pass the construction site at Gant and stop to watch a few minutes. A cra
Rama09 [41]

Answer:

30.63 m

Explanation:

Using y = ut + 1/2gt² where u = initial speed of block = 0 m/s, g = acceleration due to gravity = 9.8 m/s² and t = time of fall = 2.5 s and y = height of fall.

So, substituting the values of the variables into the equation, we have

y = ut + 1/2gt²

y = 0 m/s × 2.5 s + 1/2 × 9.8 m/s² × (2.5 s)²

y = 0 m + 4.9 m/s² × 6.25 s²

y = 0 m + 30.625 m

y = 30.625 m

y ≅ 30.63 m

So, the brick fell 30.63 m

7 0
3 years ago
Andre the Giant and Thumbelina are standing in the middle of an ice-skating rink facing each other. Andre the Giant pushes Thumb
IceJOKER [234]
I don't know for sure but i think that it is because the force him pushing her pushed him back as well

Hope i helped

3 0
3 years ago
Read 2 more answers
What is the mass of 3 m3 of a substance having density 1200 kg/m3​
adell [148]

Answer:

3600 kg

Explanation:

From the question,

Density = Mass/Volume

D = M/V.............................. Equation 1

Where D = Density of the substance, M = mass of the substance, V = Volume of the subtance.

Make M the subject of the equation

M = D×V ............................ Equation 2

Given: D = 1200 kg/m³, V = 3 m³.

Substitute these values into equation 2

M = 1200×3

M = 3600 kg.

Hence the mass of the substance is 3600 kg

4 0
2 years ago
Even though you are getting closer to the sun as you ascend into the toposphere, why does the temperature drop?
pishuonlain [190]

Answer: The lower areas of the Atmosphere have a high temperature through the heats from the ground.

Explanation: High temperature experienced on the Earth surface is majorly caused by heats from the ground ( Earth crust).As a person ascend up to the Toposphere the temperature continues to reduce because because the heat from the ground is reduced as the heights increased.

It has been proven that as a person ascends into the Toposphere the amount of air and pressure reduces this will eventually lead to expansion of the gas particles which will then reduce the temperature.

4 0
3 years ago
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