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3 years ago

One more plzzzzzzzzzzzzzzzzzzzz

Mathematics

2 answers:

padilas [110]3 years ago

8 0

Answer:

Step-by-step explanation:

$p^2+13p-30=0$

Factor:

$(p+15)(p-2)=0$

Turn roots into answers:

$p=2,-15$

The correct answer choice is B. Hope this helps!

Mnenie [13.5K]3 years ago

8 0

Answer:

p = -15 p=2

Step-by-step explanation:

p^2 +13p - 30 =0

Factor

What 2 numbers multiply to -30 and add to 13

15*-2 = -30

15 -2 = 13

(p+15) (p-2) =0

Using the zero product property

p+15 =0 p-2 =0

p = -15 p=2

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Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

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$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

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