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zepelin [54]
3 years ago
12

if the mole fractio of NaCl in an aqueous solution is 0.0927, what is the wt/wt% (percent by mass) of NaCl

Chemistry
1 answer:
Viktor [21]3 years ago
7 0

mole NaCl = 0.0927

mole H2O = 1.0000 - 0.0927 = 0.9073

then

mass NaCl = 0.0927mole x (0.9073g / mole) = 0.1022 g

mass H2O = 0.9073 mole x (18.02g / mole) = 16.35 g

and therefore;

mass % NaCl = [(0.1022g NaCl) / (58.45g NaCl + 18.016g H2O)] x 100% = 24.9%

=24.9%

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Complete Question

The complete question is shown on the first uploaded image

Answer:

The equilibrium constant is  K_c= 2.8*10^{-4}

Explanation:

      From  the question we are told that

              The chemical reaction equation is

      Fe_{2} O_{3}_{(s)} + 3H_{2}_{(g)}  -----> 2Fe_{(s)} + 3H_{2} O_{(g)}

The voume of the misture is  V_m = 5.4L  

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    The molar mass of  H_{2}_{(g)}    is a constant with value of  H_2 = 2g/mol

   

    The molar mass of  H_{2}O    is a constant with value of  H_2O = 18g/mol

Generally the number of moles  is mathematically given as

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          No \ of\ moles = \frac{3.54}{160}

                                = 0.022125 \ mols

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               No \ of\ moles = \frac{3.63}{2}

                                = 1.815 \ mols

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                         No \ of\ moles = \frac{2.13}{18}

                                              = 0.12 \ mols

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  Considering H_2O  \ for \ product

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