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il63 [147K]
3 years ago
13

Please answer FAST i will make you barinlest

Chemistry
2 answers:
Vaselesa [24]3 years ago
6 0

Answer:

Left arrow or B

Explanation:

tangare [24]3 years ago
3 0

Answer: A it goes hot to cold not cold to hot.

Explanation:

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What are the 5 steps in nuclear production​
ira [324]

The first step is splitting the atoms. Then there are control rods that absorb free floating nerons that are a result of fission. Next they heat they water pipe. Finally when they heat the pipe and water it turns to steam and they use it to harness energy!

6 0
3 years ago
HELPPP!!! What is the volume of a 1.31 moles sample of gas if the pressure is 904 mmHg and the temperature is 37. degrees Celsiu
Tju [1.3M]

Answer:

27.99 dm³

Explanation:

Applying

PV = nRT................ Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

From the question, we were aksed to find V.

Therefore we make V the subject of the equation

V = nRT/P................ Equation 2

Given: n = 1.31 moles, T = 37°C = 310K, P = 904 mmHg = (904×0.001316) = 1.1897 atm

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

V = (1.31×310×0.082)/(1.1897)

V = 27.99 dm³

4 0
3 years ago
A sample of an unknown gas takes 222 s to diffuse through a porous plug at a given temperature. At the same temperature, N2(g) t
gulaghasi [49]

Answer:

\large \boxed{\text{45.1 g/mol}}

Explanation:

Graham’s Law applies to the diffusion of gases:

The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

r \propto \dfrac{1}{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\dfrac{r_{2}}{r_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}

The time for diffusion is inversely proportional to the rate.

\dfrac{t_{2}}{t_{1}} = \sqrt{\dfrac{M_{2}}{M_{1}}}

Data:

t₂ = 222 s

 t₁ = 175 s

M₁ = 28.01

Calculation :

\begin{array}{rcl}\dfrac{222}{175} & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.269 & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.609 & = & \dfrac{M_{2}}{28.01}\\\\M_{2} & = & 1.609 \times 28.01\\ & = & \textbf{45.1 g/mol}\\\end{array}\\\text{The molar mass of the unknown gas is $\large \boxed{\textbf{45.1 g/mol}}$}

3 0
3 years ago
Can a non-polar molecule contain polar bonds? Explain your answer with an example.
Rom4ik [11]

Answer:

Yes

Explanation:

It is possible that a non polar molecule contain polar bonds.

Consider the example of CO₂:

In carbon dioxide the atoms are arranged in angle of 180 degree and molecule is linear. So in this way the net dipole movement becomes zero and molecule is non polar.

But when we see the electronegativity of both bonded atoms the oxygen is more electronegative than carbon. The oxygen atom have partial negative charge and carbon have partial positive charge because shared pair of electron is more attracted towards the oxygen. Thus bond become polar because one end is partial positive and other is partial negative. Thus a non polar carbon dioxide molecule have polar bond.

8 0
3 years ago
What are the hazards, if any of the reactants AgNO3, and K2CrO4?
Mandarinka [93]
This is what i wrote in my notebook: (for AgNO3)
<span>Health Hazards Acute and Chronic:  ACUTE:
INHALATION - MAY CAUSE SEVERE IRRITATION TO MUCOUS MEMBRANES.
SKIN - MAY CAUSE SEVERE IRRITATION.
EYE - MAY CAUSE SEVERE IRRITATION.
CHRONIC: INHALATION, SKIN & INGESTION - MAY CAUSE ARSYRIA. Explanation of Carcinogenicity:THIS COMPOUND CONTAINS NO INGREDIENTS AT CONCENTRATIONS OF 0.1% OR GREATER THAT ARE CARCINOGENS OR SUSPECT CARCINOGENS.

</span><em><u>AgNO3 + K2CrO4 = Ag2CrO4 + KNO3</u></em>

3 0
3 years ago
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