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2 years ago

I need help on career prep

1 answer:

4 0

Here is some helpful information:

- Career prep is dedicating time and energy to deciding what you want to spend doing as life work. In other words it is choosing a career.

- Career prep involves preparation, research, resources, connections, decision making....

- Career prep is meant to be a process that helps you choose the field that you will pursue . It is meant to prepare you for the career you have chosen to commit to.

- Career prep involves you asking serious questions like what i am good at? what do I like doing? what do I so well I can get paid for doing it? what do I do that I don't mind working hard every day?

I hope this helped. please vote my answer branliest. Thanks.

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Light travels 186 000 miles per second.how many miles dose light travel in one year

Troyanec [42]

(186,000 mi/sec) x (3,600 sec/hr) x (24 hr/da) x (365 da/yr)

= (186,000 x 3,600 x 24 x 365) mi/yr

= 5,865,696,000,000 miles per year (rounded to the nearest million miles)

8 0

3 years ago

An archer defending a castle is on a 15.5 m high wall. He shoots an arrow straight down at 22.8 m/s. How much time does it take

vazorg [7]

Answer: 1.907

Explanation:

I did the math

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3 years ago

At what height is an object that weighs 490 newtons if its gravitational potential energy is 4900 J?

Sergio [31]

Answer:

The height at which the object is moved is 10 meters.

Explanation:

Given that,

Force acting on the object, W = F = 490 N

The gravitational potential energy, P = 4900 J

We need to find the height at which the object is moved. We know that the gravitational potential energy is possessed due to its position. It is given by :

$P=mgh\\\\h=\dfrac{P}{mg}\\\\h=\dfrac{4900\ J}{490\ N}\\\\h=10\ m$

So, the height at which the object is moved is 10 meters. Hence, this is the required solution.

5 0

3 years ago

A bus covers 200m in 5 second.Calculate its speed.

QveST [7]

The answer is 40m/s

7 0

2 years ago

Read 2 more answers

An ammeter with a resistance of 5.0 ohm is connected in series with a 3.0V cell and a lamp rated at 300 mA, 3V. Calculate the cu

Alex

Answer:

I = 0.2 A

Explanation:

Lamp is rated at 300 mA

I_lamp = 0.3 A

Voltage is; V = 3V

Thus; Resistance is given by;

R = V/I

R = 3/0.3

R = 10 ohms

Now, since the ammeter of 5 ohms is connected in series with the lamp. Thus equivalent resistance;

R_eq = 10 + 5

R_eq = 15 ohms

Ammeter current will be;

I = V/R_eq

I = 3/15

I = 0.2 A

3 0

2 years ago