All categories

3 years ago

What is the frequency of blue light that has a wavelength of 446 nm?

2 answers:

7 0

When I went through with the math, the answer I came upon was:
6.67 X 10^14 

Here is how I did it: First of all we need to know the equation. 

c=nu X lamda 
(speed of light) = (frequency)(wavelength) 
(3.0 X 10^8 m/s) = (frequency)(450nm) 

We want the answer in meters so we need to convert 450nm to meters. 
450nm= 4.5 X 10^ -7 m 
(3.0 X 10^8 m/s) = (frequency)(4.5 X 10^ -7 m) 

Divide the speed of light by the wavelength. 
(3.0 X 10^8m/s) / (4.5 X 10^ -7m) =6.67 X 10^ 14 per second or s- 

Answer: 6.67 X 10^14 s- hope this helps

BartSMP [9]3 years ago

3 0

From Electromagnetic Waves,
Velocity C = f *λ

Where C = Velocity in m/s. = 3 * 10^8 m/s.
f = Frequency in Hertz    ( /s)
   λ = Wavelength in metres.

Wavelength of blue light = 446 nm = 446 nano metres = 446 * 10^-9 m.

f = C / λ = ( 3 *10^8) / (446 * 10^-9) use your calculator.
   = 6.7265 * 10 ^ 14 Hertz.

You might be interested in

Which of the following is not an example of Newton’s third law?

Mrrafil [7]

C) All of these are examples of Newton’s third law.

3 0

3 years ago

A 5-kg ball collides inelastically head-on with a 10-kg ball, which is initially stationary. Which of the following statements i

Veseljchak [2.6K]

a. The magnitude of the change of the momentum of the 5-kg ball is equal to the magnitude of the change of momentum of the 10-kg ball.

c. The magnitude of the change of velocity the 5-kg ball experiences is greater than that of the 10-kg ball.

Explanation:

For an inelastic collision:

The total momentum of the system is conserved
The total kinetic energy of the system is not conserved

Using these facts, let's now analyze each statement given.

a. The magnitude of the change of the momentum of the 5-kg ball is equal to the magnitude of the change of momentum of the 10-kg ball. --> TRUE. Since the total momentum is conserved, we can write:

$p_1 = p_1'+p_2'$

where

$p_1$ is the initial momentum of the 5-kg ball

$p_1'$ is the final momentum of the 5-kg ball

$p_2'$ is the final momentum of the 10-kg ball

The equation can be rewritten as

$p_1-p_1'=p_2'$

which is equivalent to

$-\Delta p_1 = \Delta p_2$

which means that the magnitude of the change of momentum of the two balls is the same.

b. Both balls lose all their momentum since the collision is inelastic. --> FALSE, the 10-kg ball gains momentum, so it does not lose it.

c. The magnitude of the change of velocity the 5-kg ball experiences is greater than that of the 10-kg ball. --> TRUE. We already said that the magnitude of the change in momentum of the two balls is the same. However, it can be written as

$\Delta p = m\Delta v$

where m is the mass of the ball and $\Delta v$ its change in velocity. Therefore, the 5-kg ball (which has smaller mass) will have a larger $\Delta v$ , so a larger change in velocity.

d. The magnitude of the change of velocity the 5-kg ball experiences is equal to that of the 10-kg ball. --> FALSE, as we discussed in c).

e. The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball. --> FALSE, as we discussed in c).

Learn more about change in momentum:

brainly.com/question/9484203

#LearnwithBrainly

6 0

3 years ago

A metal detector used in airports is actually a large coil of wire carrying a small current. Explain how it detects a gun, even

Alexus [3.1K]

Metal detectors work by transmitting an electromagnetic field from the search coil into the ground. Any metal objects (targets) within the electromagnetic field will become energised and retransmit an electromagnetic field of their own. The detector’s search coil receives the retransmitted field and alerts the user by producing a target response. metal detectors are capable of discriminating between different target types and can be set to ignore unwanted targets.

1. Search Coil

The detector’s search coil transmits the electromagnetic field into the ground and receives the return electromagnetic field from a target.

2. Transmit Electromagnetic Field (visual representation only - blue)

The transmit electromagnetic field energises targets to enable them to be detected.

3. Target

A target is any metal object that can be detected by a metal detector. In this example, the detected target is treasure, which is a good (accepted) target.

hope this helps PLEASE MARK AS BRAINLIEST:)

8 0

3 years ago

A 100g block is initially compressing a spring 5.0 cm. The spring launches the block 50cm horizontally along the ground with a f

Setler [38]

Answer:

7200 N/m

Explanation:

Metric unit conversion

100g = 0.1 kg

5 cm = 0.05 m

50 cm = 0.5 m

As the block is released from the spring and travelling to height h = 1.5m off the ground, the elastics energy is converted to work of friction force and the potential energy at 1.5 m off the ground

The work by friction force is the product of the force F = 15N itself and the distance s = 0.5 m

$W_f = F_fs = 15*0.5 = 7.5 J$

Let g = 10 m/s2. The change in potential energy can be calculated as the following:

$E_p = mgh = 0.1*10*1.5 = 1.5 J$

Therefore, as elastic energy is converted to potential energy and work of friction:

$E_e = W_f + E_p$

$kx^2/2 = 7.5 + 1.5 = 9 J$

$k = 9*2/x^2 = 18/0.05^2 = 7200 N/m$

6 0

3 years ago

A 2 microcoulomb charge is placed at a distance of 0.25 m away from a 3.6 microcoulomb charge. Describe the type of electrostati

EleoNora [17]

Answer: 1.04N

Explanation:

Given

q1 = 2*10^-6C

q2 = 3.6*10^-6C

r = 0.25m

k = 9*10^9

Magnitude of electrostatic force can be calculated by using coulomb's law. Coulomb's law states that, "the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them."

F =(kq1q2) / r²

F = (9*10^9 * 2*10^-6 * 3.6*10^-6) / 0.25²

F = 0.0648/0.0625

F = 1.04N

The type of electrostatic force between the charges is the repulsive force

7 0

3 years ago

Read 2 more answers