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3 years ago

What is the frequency of blue light that has a wavelength of 446 nm?

2 answers:

7 0

When I went through with the math, the answer I came upon was:
6.67 X 10^14 

Here is how I did it: First of all we need to know the equation. 

c=nu X lamda 
(speed of light) = (frequency)(wavelength) 
(3.0 X 10^8 m/s) = (frequency)(450nm) 

We want the answer in meters so we need to convert 450nm to meters. 
450nm= 4.5 X 10^ -7 m 
(3.0 X 10^8 m/s) = (frequency)(4.5 X 10^ -7 m) 

Divide the speed of light by the wavelength. 
(3.0 X 10^8m/s) / (4.5 X 10^ -7m) =6.67 X 10^ 14 per second or s- 

Answer: 6.67 X 10^14 s- hope this helps

BartSMP [9]3 years ago

3 0

From Electromagnetic Waves,
Velocity C = f *λ

Where C = Velocity in m/s. = 3 * 10^8 m/s.
f = Frequency in Hertz    ( /s)
   λ = Wavelength in metres.

Wavelength of blue light = 446 nm = 446 nano metres = 446 * 10^-9 m.

f = C / λ = ( 3 *10^8) / (446 * 10^-9) use your calculator.
   = 6.7265 * 10 ^ 14 Hertz.

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The first law of thermodynamics states that energy can neither be created nor destroyed. If this is true then why are we always

riadik2000 [5.3K]

Answer:

The second law of thermodynamics states in an isolated system, the entropy (the amount of thermal energy that cannot be converted into mechanical work, also known as the amount of disorder) always increases, therefore, an isolated system always require an external input (new sources) of energy for there to be orderliness or for the available energy of the system to remain constant or increase

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2 years ago

A friend asks you how much pressure is in your car tires. You know that the tire manufacturer recommends 30 psi, but it's been a

Rama09 [41]

Answer:

21 psi

Explanation:

The weight of the car is:

W = mg

W = 1000 kg * 9.8 m/s²

W = 9800 N

Divided by 4 tires, each tire supports:

F = W/4

F = 9800 N / 4

F = 2450 N

Pressure is force divided by area, so:

P = F / A

P = (2450 N) / (0.13 m × 0.13 m)

P ≈ 145,000 Pa

101,325 Pa is the same as 14.7 psi, so:

P ≈ 145,000 Pa × (14.7 psi / 101,325 Pa)

P ≈ 21 psi

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3 years ago

a car initially at 65.00 m/s accelerates at 22.39 m/s^2. How far has the car traveled before it comes to a stop

Gennadij [26K]

Answer:

94.35 meter

Step by step explanation

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2 years ago

Which of the following statements is accurate?

cupoosta [38]

Answer: A and B

Explanation:

The wavelength of both transverse and longitudinal waves is measured parallel to the direction of the travel of the wave.

Because wavelength is the distance between the two successful crest or trough.

Amplitude of longitudinal waves is measured at right angles to the direction of the travel of the wave and represents the maximum distance the molecule has moved from its normal position.

Because amplitude is the measure of maximum displacement from the original position

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2 years ago

Suppose an electron is trapped within a small region and the uncertainty in its position is 24.0 x 10-15 m. What is the minimum

Alina [70]

Answer:

Uncertainty in position (∆x) = 24 × 10⁻¹⁵ m
Uncertainty in momentum (∆P) = ?
Planck's constant (h) = 6.26 × 10⁻³⁴ Js

$\longrightarrow \: \: \sf\Delta x .\Delta p = \dfrac{h}{4\pi}$

$\longrightarrow \: \: \sf24 \times {10}^{ - 15} .\Delta p = \dfrac{6.26 \times {10}^{ - 34}} {4 \times \frac{22}{7} }$

$\longrightarrow \: \: \sf24 \times {10}^{ - 15} .\Delta p = \dfrac{6.26 \times {10}^{ - 34}} { \frac{88}{7} }$

$\longrightarrow \: \: \sf24 \times {10}^{ - 15} .\Delta p = \dfrac{6.26 \times {10}^{ - 34} \times 7} { 8 }$

$\longrightarrow \: \: \sf\Delta p = \dfrac{43.82 \times {10}^{ - 34} } { 8 \times 24 \times {10}^{ - 15} }$

$\longrightarrow \: \: \sf\Delta p = \dfrac{43.82 \times {10}^{ - 34} } { 192 \times {10}^{ - 15} }$

$\longrightarrow \: \: \sf\Delta p = \dfrac{43.82 \times {10}^{ - 34} \times {10}^{15} } { 192}$

$\longrightarrow \: \: \sf\Delta p = \dfrac{43.82 \times {10}^{ -19} } { 192}$

$\longrightarrow \: \: \sf\Delta p = \dfrac{4382 \times {10}^{ - 2} \times {10}^{ -19} } { 192}$

$\longrightarrow \: \: \sf\Delta p = \dfrac{4382 \times {10}^{ - 21} } { 192}$

$\longrightarrow \: \: \sf\Delta p = 22.822\times {10}^{ - 21}$

$\longrightarrow \: \: \sf\Delta p = 2.2822 \times {10}^{1} \times {10}^{ - 21}$

$\longrightarrow \: \: \underline{ \boxed{ \red{ \bf\Delta p = 2.2822 \times {10}^{ - 20} \: kg/ms}}}$

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2 years ago