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AfilCa [17]
3 years ago
5

A 12.0 cm object is 9.0 cm from a convex mirror that has a focal length of -4.5 cm. What is the distance of the image from the m

irror? –3 cm –4 cm 3 cm 4 cm
Physics
1 answer:
Rasek [7]3 years ago
5 0

Answer:

- 3 cm

Explanation:

From the mirror formula;

1/f = 1/v + 1/u ; where f is the focal length, v is the image distance, and u is the object distance.

1/-4.5 = 1/9 + 1/v

1/v = -1/4.5 - 1/9

    = -1/3

Therefore;

v = -3 cm

Hence;

Image distance is - 3cm

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A car is initially driving at 30 m/s. It hits a large pothole, after which it is traveling in the same direction but at 25 m/s.
Bogdan [553]

Answer:

The time of Mars is 1.65 times larger on Mars than on Earth

Explanation:

The equation that describes the system is the final speed is equal to the speed minos the speed lost by the collision with the porhole

       Vf = Vo - V pothole

B) let's transform the weight of free groin system and N international system

      1 N = 0.2248 lb

      2.8 lbs (1N / 0.2248lbs) = 12.5 N

c) Kinematic equations are the same in all inertial systems, Mars and Earth, so we can use the height equation, with zero initial velocity

                   

        Y = Vo t - ½ g t²

        Y = - ½ g t²

        t = √ 2Y / g

     

Mars

         gm = 0.37g

         gm = 0.37 9.8

         gm = 3,626 m / s²

         t = √( 2 1.9 / 3.626 )

         t = 1.02 s

Earth

         t = √( 2 1.9 / 9.8)

         t = 0.62 s

To make the comparison of time we are the relationship between the two

         tm / te = 1.02 / 0.62

         tm / te = 1.65

The time of Mars is 1.65 times larger on Mars than on Earth

7 0
3 years ago
Read 2 more answers
Mike has a mass of 97 kg. He jumps out of a perfectly good airplane that is 2000 m above the ground. After he falls 1000 m, when
Ne4ueva [31]

Answer:

a)  fr = 224.3 N , b)   fr = 224.3 N , c)   v = 198.0  m/s

Explanation:

a) For this exercise let's start by calculating the acceleration in the fall

             v² = v₀² - 2 a (y-y₀)

When it jumps the initial vertical speed is zero

             a = -v² / 2 (y-y₀)

             a = -68 2/2 (1000-2000)

             a = 2,312 m / s²

Let's use the second net law to enter the average friction force

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            fr = 97 2,312

            fr = 224.3 N

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            v² = v₀² - 2 a y

            a = (v² –v₀²) / 2 (y-y₀)

            a = (4² - 68²) / 2 (0-1000)

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            fr = m a

            fr = 97 2,304

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           v² = v₀² - 2 g (y-y₀)

           v = √ (0-2 9.8 (0-2000))

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3 years ago
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skad [1K]

\frac{100}{0.214+-0.006} = 454.55 g/cm3

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Yes that answer is correct because sometimes tides cause waves to happen
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