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denis23 [38]
3 years ago
13

Which measurement is used to determine if an object has balanced forces

Physics
1 answer:
Aleonysh [2.5K]3 years ago
3 0

Answer:

a spring scale

Explanation:

i think it is correct

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6. Is 50 m/s that’s the answer
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why does chelsea see sparks as she removes her clothes from the clothes dryer? conduction. induction. static discharge. loss of
ollegr [7]

Answer:

It would be static discharge and conduction

Explanation:

The conduction of static energy is pulled throughout the clothes and left over static electricity is what causes the spark.

4 0
3 years ago
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Describe what happens when you jump from a small boat onto a dock from the perspective of the 3rd Law.
IgorLugansk [536]

according to newton's third law, every action has equal and opposite reaction. in this scenario of making a jump from the boat onto a dock, as i jump my feet in contact with the boat push the boat in backward direction. hence the action force is the push by my feet on the boat. the boat reacts by applying a reaction force on my feet pushing the feet in forward direction. hence reaction force here is the force by the boat on the feet. due to the reaction force of the boat on feet, i am pushed in forward direction to reach the the dock.

5 0
4 years ago
A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00 m above the ground. At th
Elis [28]

Answer:

  • <u>The water ballon that was thrown straight down at 2.00 m/s hits the ground first, 0.19 s before the other ballon.</u>

Explanation:

The motions of the two water ballons are ruled by the kinematic equations:

  • y=y_0+V_0t-gt^2/2

We are only interested in the vertical motion, so that equation is all what you need.

<u>1. Water ballon is thrown horizontally at sped 2.00 m/s.</u>

The time the ballon takes to hit the ground is independent of the horizontal speed.

Since 2.00 m/s is a horizontal speed, you take the initial vertical speed equal to 0.

Then:

y=y_0+V_0t-gt^2/2\\ \\ 0=6.00m-9.8\frac{m}{s^2} t^2/2\\ \\ t=\sqrt{2\times6.00m/9.8\frac{m}{s^2}}\\\\ t=1.11s

<u>2. Water ballon thrown straight down at 2.00 m/s</u>

Now the initial vertical speed is 2.00 m/s down. So, the equation is:

0=6.00m-2.00\frac{m}{s}t-9.8\frac{m}{s^2}t^2/2\\ \\ 4.9t^2+2t-6=0\\ \\ t=0.92s

To solve the equation you can use the quadratic formula.

t=\frac{-2+/-\sqrt{2^2-4(4.9)(-6)} }{2(4.9)}\\ \\ t=-1.33\\ \\ t=0.92

You get two times. One of the times is negative, thus it does not have physical meaning.

<u>3. Conclusion:</u>

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

5 0
3 years ago
If you increase the frequency what happens to the distance between the waves (wavelength)?
Dahasolnce [82]

Answer:

C)the distance decreases Shorter wavelength

Step by step Explanation:

5 0
3 years ago
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