Answer:
16,18,22
Or
1,3,7
Explanation:
The detailed explanation is contained in the image attached. The lengths are found using Pythagoras theorem and the two lengths reflects the two values of x yielded by the quadratic equation
Answer:

Explanation:
a) Fundamental frequency
A harmonic is an integral multiple of the fundamental frequency.


b) Wave speed
(i) Calculate the wavelength
In a fundamental vibration, the length of the string is half the wavelength.

(b) Calculate the speed
s



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