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4 years ago

14

An object of mass 50 kg accelerates from a velocity of 2.0 m/s to a velocity of 10 m/s in the same direction in 4.0 s.

1 answer:

MrMuchimi4 years ago

5 0

Answer:

the displacement would be 32 m

Explanation:

there is no formula for displacement, but you can use the velocity formula as you have the velocity and time so it looks like:

$8 = \frac{x}{4}$

with x being the displacement

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Answer:

Reflection of Light. When light waves are incident on a smooth, flat surface, they reflect away from the surface at the same angle as they arrive. ... Regardless of whether light is acting as particles or waves, however, the result of reflection is the same.

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4 years ago

To find the number of neutrons in an atom you would subtract?

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8 0

3 years ago

Please help Need good grade

ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the range

Using formula of range

$R=\dfrac{v^2\sin(2\theta)}{g}$ ...(I)

The range for the other angle is

$R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}$ ....(II)

Here, distance and speed are same

On comparing both range

$\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}$

$\sin(2\theta)=\sin(2\times(\alpha-\theta))$

$\sin120=\sin2(\alpha-60)$

$120=2\alpha-120$

$\alpha=\dfrac{120+120}{2}$

$\alpha=120^{\circ}$

Hence, The other angle is 120°

6 0

4 years ago

What is the net force exerted on a 28.8 kg shopping cart that accelerates at a rate of 2.88 m/s^2?

Mama L [17]

Answer:

<h2>82.94 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 28.8 × 2.88 = 82.944

We have the final answer as

<h3>82.94 N</h3>

Hope this helps you

6 0

3 years ago

An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a ra

lukranit [14]

Answer:

$\frac{dA}{dt} = 28800 \ m^2/year$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

<u>Geometry</u>

Area of a Rectangle: A = lw

<u>Algebra I</u>

Exponential Property: $w^n \cdot w^m = w^{n + m}$

<u>Calculus</u>

Derivatives

Differentiating with respect to time

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Explanation:

<u>Step 1: Define</u>

Area is A = lw

2w = l

w = 300 m

$\frac{dw}{dt} = 24 \ m/year$

<u>Step 2: Rewrite Equation</u>

Substitute in <em>l</em>: A = (2w)w
Multiply: A = 2w²

<u>Step 3: Differentiate</u>

<em>Differentiate the new area formula with respect to time.</em>

Differentiate [Basic Power Rule]: $\frac{dA}{dt} = 2 \cdot 2w^{2-1}\frac{dw}{dt}$
Simplify: $\frac{dA}{dt} = 4w\frac{dw}{dt}$

<u>Step 4: Find Rate</u>

<em>Use defined variables</em>

Substitute: $\frac{dA}{dt} = 4(300 \ m)(24 \ m/year)$
Multiply: $\frac{dA}{dt} = (1200 \ m)(24 \ m/year)$
Multiply: $\frac{dA}{dt} = 28800 \ m^2/year$

3 0

3 years ago

Read 2 more answers