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4 years ago

An object of mass 50 kg accelerates from a velocity of 2.0 m/s to a velocity of 10 m/s in the same direction in 4.0 s.

Physics

1 answer:

MrMuchimi4 years ago

5 0

Answer:

the displacement would be 32 m

Explanation:

there is no formula for displacement, but you can use the velocity formula as you have the velocity and time so it looks like:

$8 = \frac{x}{4}$

with x being the displacement

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A car travels north for 20 km. The car then travels south for 35 km.

PSYCHO15rus [73]

Answer: -15 km

Explanation:

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3 years ago

How many significant figures does 50.003 00 have?

Serhud [2]

5 sig figs I think that

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3 years ago

How would the amount of carbon dioxide in the atmosphere change if they were no plants?

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3 years ago

Identify each of the quantities below as either vector or scalar

natta225 [31]

Answer:

2nd answer 3.2m/s is a scalar l, all others are vectors.

Explanation:

In order to be considered as a vector a certain quantity must have both a magnitude and a direction.

The most common example is velocity. It has both magnitude and direction, like the 1st and the last answers.

The 3rd answer is an acceleration. It is also given with its direction. So we have to consider it also as a vector.

But 2nd answer has no direction mentioned, so it is considered as a scalar.

7 0

3 years ago

A spaceship ferrying workers to moon Base i takes a straight-line pat from the earth to the moon, a distance of 384,000km, Suppo

GrogVix [38]

Answer:

95.78125%

18000 m/s

22233.33 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v=u+at\\\Rightarrow v=0+20\times 15\times 60\\\Rightarrow v=18000\ m/s$

The velocity of the rocket at the end of the first 15 minutes is 18000 m/s which is the maximum speed of the rocket in the complete journey.

Distance traveled while speeding up

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 20\times 900^2\\\Rightarrow s=8100000\ m$

Distance traveled while slowing down

$s=18000\times 900+\dfrac{1}{2}\times -20\times 900^2\\\Rightarrow s=8100000\ m$

Distance traveled during constant speed

$384000000-(2\times 8100000)=367800000\ m$

Fraction

$\dfrac{367800000}{384000000}\times 100=95.78125\ \%$

Fraction of the total distance is traveled at constant speed is 95.78125%

Time taken at constant speed

$t=\dfrac{367800000}{18000}=20433.33\ s$

Total time taken is $900+20433.33+900=22233.33\ s$

6 0

3 years ago