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VMariaS [17]
3 years ago
10

A bowling ball collides with a tennis ball. Which object has the larger impact force on the other considering that they have the

same acceleration? Why?
This is for an exam could you please answer fast
Physics
1 answer:
Bezzdna [24]3 years ago
4 0

Answer:

The tennis ball experiences a larger impact force due to its smaller mass.

Explanation:

Considering that they have the same acceleration, and F = ma where F is force and m = mass, the object with the smaller mass has a greater impact force on it.

This is because since force F = ma and a = constant, the object with a larger mass (the bowling ball)has a larger impact force with which it acts on the object with the smaller mass (the tennis ball). So, the tennis ball experiences a larger impact force due to its smaller mass.

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Explanation:

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v_{ix}=9m/s, v_{iy}=-6m/s, v_{iz}=0m/s\\v_{fx}=8.96m/s, v_{fy}=-6.12m/s, v_{fz}=0m/s\\t=0.02s, m=0.12Kg

We can calculate each component of the acceleration using its definition a=\frac{\Delta v}{\Delta t}

a_x=\frac{v_{fx}-v_{ix}}{t} = \frac{(8.96m/s)-(9m/s)}{0.02s} =-2m/s^2\\a_y=\frac{v_{fy}-v_{iy}}{t} = \frac{(-6.12m/s)-(-6m/s)}{0.02s} =-6m/s^2\\a_y=\frac{v_{fz}-v_{iz}}{t} = \frac{(0m/s)-(0m/s)}{0.02s} =0m/s^2\\

The rate of change of momentum of the ball is \frac{\Delta p}{\Delta t} = \frac{\Delta mv}{\Delta t} = \frac{m\Delta v}{\Delta t} = ma

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\frac{\Delta p_x}{\Delta t}=-0.24Kgm/s^2\\\frac{\Delta p_y}{\Delta t}=-0.72Kgm/s^2\\\frac{\Delta p_z}{\Delta t}=0Kgm/s^2

And these are equal to the components of the net force since F=ma.

If magnitudes is what is asked:

a=\sqrt{a_x+a_y+a_z} =6.3m/s^2\\F=ma=\frac{\Delta p}{\Delta t}=0.76N

<em>(N and </em>Kgm/s^2<em> are the same unit).</em>

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