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djverab [1.8K]
3 years ago
5

What is the type of bonding for ammonium lauryl sulfate?

Chemistry
1 answer:
DENIUS [597]3 years ago
7 0

Answer:

Hydrogen bonding.

Explanation:

Ammonium lauryl sulfate is also known as ammonium dodecyl sulfate there are two parts in Ammonium lauryl sulfate one is nonpolar hydrocarbon and other part polar sulfate group.

Due to polarity of sulfate group its form hydrogen bond very easily.

It is mainly used as foaming agent the main reason of its use is very much soluble in water and making hydrogen bond with water.

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Explanation:

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Given the equation: 2H2 + O2 → 2H2O, how many moles of oxygen are needed to react with 13 moles of hydrogen
bulgar [2K]

Explanation:

2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=<u>13mol</u><u> </u><u>×</u><u> </u><u>1mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2mol</u>

x= <u>13mol</u>

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6 0
2 years ago
The standard enthalpy of combustion of naphthalene is –5157 kj mol-1. calculate its standard enthalpy of formation. (use data in
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The combustion of naphthalene is given as:

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Enthalpy of combustion ΔH = -5157 kJ/mol

Now, the enthalpy change of a reaction is given

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Therefore,

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ΔHf(C10H8) = 78.68 kJ/mol

4 0
3 years ago
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