Answer:
The molar concentration of
ions in the given amount of sample is 
Explanation:
Given that,
Mass of sample = 21.5 g
0.07 % (m/m) of copper (II) sulfate in plant fertilizer
This means that, in 100 g of plant fertilizer, 0.07 g of copper (II) sulfate is present
So, in 20 g of plant fertilizer
,
of copper (II) sulfate is present.
To calculate the molarity of solution, we use the equation:

Mass of solute (copper (II) sulfate) = 0.0151 g
Molar mass of copper (II) sulfate = 159.6 g/mol
Volume of solution = 2.0 L

The chemical equation for the ionization of copper (II) sulfate follows:

1 mole of copper (II) sulfate produces 1 mole of copper (II) ions and sulfate ions
Molarity of copper (II) ions = 
Hence, the molar concentration of
ions in the given amount of sample is 