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Rainbow [258]
4 years ago
6

Predict whether ΔS° is greater than, less than, or approximately zero for each of the following reactions, and explain your choi

ce. (a) 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) (b) CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g) (c) CaCO3(s) → CaO(s) + CO2(g)
Chemistry
1 answer:
inna [77]4 years ago
8 0

Answer:

Explanation:

Entropy -

In a system, the randomness is measured by the term entropy .

Randomness basically refers as a form of energy that can not be used for any work.

The change in entropy is given by amount heat per change in temperature.

  • When solid is converted to gas entropy increases,

As the molecules in solid state are tightly packed and has more force of attraction between the molecules, but as it is converted to gas, the force of attraction between the molecule decreases and hence entropy increases.

So,

The particles of the substance , if are tightly held by strong force of attraction will decrease the entropy ,

And

If the particles are loosely held , the entropy will increase .  

  • If in a reaction , more number of gaseous atoms are present in the product side , entropy will increase , i.e. Δ°S > 0
  • When liquid is converted to solid entropy decreases,  

As the molecules in liquid state are loosely packed and has less force of attraction between the molecules, but as it is converted to solid, the force of attraction between the molecule increases and hence entropy decreases.

  • If in a reaction , less number of gaseous atoms are present in the product side , entropy will decrease , i.e. Δ°S < 0

From the question ,

( a )  NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)

Gaseous atoms -

Reactant - 1 + 5 = 6

Product - 4 + 6 = 10 ,

Hence ,

More number of gaseous atoms are present in the product side , So ,

entropy will increase , i.e. Δ°S > 0

( b ) CH₄(g) + 2 O₂(g) → CO₂(g) + 2 H₂O(g)

Gaseous atoms -

Reactant - 1 + 2 = 3

Product - 1 + 2 = 3 ,

Since ,

Both the side the value of gaseous atoms are , hence , Δ°S = 0 .

( c ) CaCO₃(s) → CaO(s) + CO₂(g)

Gaseous atoms -

Reactant = 0

Product - 0 + 1 = 1 ,

Since ,

Hence ,

More number of gaseous atoms are present in the product side , So ,

entropy will increase , i.e. Δ°S > 0

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It's sunny in new york, but it is cool. where would you expect to find this lizard during the day? question 16 options: under a
frez [133]

It's sunny in new york, but it is cool, we will expect to find lizard under a rock or in a hole in the ground.

<h3>Why lizards are not comfortable in cold?</h3>

Lizards are not comfortable in the cold season as they are cold blooded animal, so their body will gets slow in the winter season.

During the winter season or in the cool weather, lizards will go to the places where they faces less cooling. And these places be like inside the rocks, under a hole, under the ground, in the trunks of trees, etc.

Hence, options (1) and (4) are correct.

To know more about lizards, visit the below link:

brainly.com/question/407800

5 0
3 years ago
A airliner has an internal pressure of 1.00 ATM and temperatures of 25°C at take off if the temperature of the airlines routes t
Georgia [21]

Answer:

Explanation:

Using Gay lussac's law equation as follows;

P1/T1 = P2/T2

7 0
3 years ago
A 8.249 gram sample of copper is heated in the presence of excess fluorine. A metal fluoride is formed with a mass of 13.18 g. D
levacccp [35]

Answer:

CuF_2 the empirical formula of the metal fluoride.

Explanation:

Mass of copper heated = 8.249 g

Mass of copper fluoride formed = 13.18 g

Mass of fluorine gas in copper fluoride = x

13.18 g = 8.249 g + x\\x= 13.18 - 8.249 g = 4.931 g

Moles of copper :

= \frac{8.249 g}{63.546 g/mol}=0.1298 mol

Moles of fluorine:

= \frac{4.931 g}{18.998 g/mol}=0.2596 mol

For the empirical formula divide the smallest mole of an element with all the moles of elements present in the compound.

Copper= \frac{0.1298 mol}{0.1298 mol}=1\\Fluorine = \frac{0.2596 mol}{0.1298 mol}=2

The empirical formula of the copper fluoride = CuF_2

CuF_2 the empirical formula of the metal fluoride.

6 0
3 years ago
Show the curved-arrow mechanism for the Claisen condensation of ethyl ethanoate treated with ethoxide ion. Include all formal ch
Anna [14]

Answer:

See explaination

Explanation:

Please kindly check out the attached files for the curved-arrow mechanism for the Claisen condensation of ethyl ethanoate treated with ethoxide ion.

4 0
3 years ago
Starting with: Lithium atomic mass: 7 g/mol atomic number: 3 Use Lithium as a starting place for A, B, and C. What would happen
marshall27 [118]

Answer:

a. _3^7Li

b. _{3}^{7}Li^+

c. _{3}^{8}Li

d. _{2}^{4}He^+

Explanation:

Given lithium with atomic mass (M = 7) and atomic number (Z = 3), we may write it in a standard notation placing the atomic mass as a superscript and the atomic number as a subscript:

_3^7Li

a. Atomic number corresponds to the total number of protons a species has. Adding a proton to lithium would increase the atomic number by 1 unit. Besides, changing the atomic number would also change the element, as each element has a unique atomic number.

It's also important to remember that mass of an atom consists of a sum of protons and neutrons, so we'd also have to add 1 to the mass number. Therefore, we would have some species X with:

_{3+1}^{7+1}X=_{4}^{8}X

Now we need to identify X finding an element with Z = 4 in the periodic table. This is beryllium:

_{4}^{8}Be

b. Standard lithium atom has an atomic number of 3, this means it has 3 protons. Since we have an atom, the positive charge provided by protons is equal to the negative charge provided by electrons. This implies that a neutral atom has the same number of protons and electrons.

We start with 3 electrons in lithium. Removing an electron would produce a lithium cation with a +1 charge, as we now have a net charge of +3 from protons and -2 from electrons.

Therefore, we may represent this as lithium cation with a +1 charge:

_{3}^{7}Li^+

c. Neutrons don't have a charge but they are a component of the total mass an atom has. Essentially, adding a neutron wouldn't change the overall charge (the atomic number) of lithium.

However, adding a neutron would cause the mass to increase by 1, as each neutron (as well as proton) weighs 1 atomic mass unit. Since the atomic number doesn't change, the element would still be lithium in that case:

_{3}^{7+1}Li=_{3}^{8}Li

d. Firstly, we remove a proton, this means the atomic number of Li decreases by 1 unit, as an atomic number is equal to the number of protons:

Z=3-1=2

The mass would also decrease by 1 unit, as mass contains the number of protons and neutrons:

M=7-1=6

That said, upon performing the first step, we have helium (atomic number of 2 in the periodic table) with a mass of 6:

_{2}^{6}He

Now, we also remove 2 neutrons. This means the mass decreases by 2 units and the charge of He remains constant, as no protons are involved in this step and neutrons don't change the charge of a nucleus:

_{2}^{6-2}He=_{2}^{4}He

Finally, an electron is removed. Removing an electron would produce a helium cation with charge +1, as we'd have 2 protons and 1 remaining electron upon removing 1 electron from helium that has a total of 2 electrons in its atomic state:

_{2}^{4}He^+

3 0
3 years ago
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