Answer:
k=-6x
Step-by-step explanation:
You are looking for the value of k.
Either (6x+k)=0, or (3x-11)=0 because of the Zero Product Property
We are looking for k, so we must make (6x+k)=0
Simply cancel 6x out by subtracting 6x.
6x-6x=0.
Slope is (y2-y1)/(x2-x1)
(-3-4)/(-1- -1) = -7/0
since numbers are not divisible by 0
the slope is undefined
the line is a vertical line with an undefined slope
Answer:
none of them its <
Step-by-step explanation:
![\sin^2x=2\sin x+3](https://tex.z-dn.net/?f=%5Csin%5E2x%3D2%5Csin%20x%2B3)
![\sin^2x-2\sin x-3=0](https://tex.z-dn.net/?f=%5Csin%5E2x-2%5Csin%20x-3%3D0)
![(\sin x-3)(\sin x+1)=0](https://tex.z-dn.net/?f=%28%5Csin%20x-3%29%28%5Csin%20x%2B1%29%3D0)
which means either
![\sin x=3](https://tex.z-dn.net/?f=%5Csin%20x%3D3)
or
![\sin x=-1](https://tex.z-dn.net/?f=%5Csin%20x%3D-1)
. The equation has no solution, since
![\sin x](https://tex.z-dn.net/?f=%5Csin%20x)
is always bounded between -1 and 1. The second has one solution at
![x=-\dfrac\pi2](https://tex.z-dn.net/?f=x%3D-%5Cdfrac%5Cpi2)
, and any number of complete revolutions will also satisfy this equation, so in general the solution would be
![-\dfrac\pi2+2k\pi](https://tex.z-dn.net/?f=-%5Cdfrac%5Cpi2%2B2k%5Cpi)
where
![k](https://tex.z-dn.net/?f=k)
is any integer.
So you could choose
![A=-\dfrac\pi2](https://tex.z-dn.net/?f=A%3D-%5Cdfrac%5Cpi2)
and
![B=2](https://tex.z-dn.net/?f=B%3D2)
.