3 years ago

PLEASE HELP DUE TOMMOROW!!!!!

Mathematics

1 answer:

Marta_Voda [28]3 years ago

8 0

Let X= # of days, y= finial cost. Part A= 12+7x=y. Part B= 12+7(18)= $138. Part c= 12+7(187)= $1,321

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In triangle abc, the measure of angle b is 20 more than three times the measure of angle

sleet_krkn [62]

Let x be the degree of angle a.

Angle b: 20+3x
Angle c: 55+x

We know that all angles add up to 180 degrees.

180=x+(20+3x)+(55+x)
180= 5x+75
180-75=5x
105/5=x
21=x

Angle a: 21 degrees
Angle b: 20+3(21) => 83 degrees
Angle c: 21+55 => 76 degrees

Hope I helped :)

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%282w%20%2B%201%29%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="(2w + 1) {}^{2} " alt="(2w +

Lynna [10]

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Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If the points (-8, 7) and T (6,-3) are on a line segment, find the length of ST.

larisa86 [58]

Answer:

The answer is

<h2>2√74 or 17.20 units</h2>

Step-by-step explanation:

The length of w line segment between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

S(-8, 7) and T (6,-3)

The length of ST is

$|ST| = \sqrt{ ({ - 8 - 6})^{2} + ({7 + 3})^{2} } \\ = \sqrt{ ({ - 14})^{2} + {10}^{2} } \\ = \sqrt{196 + 10} \\ = \sqrt{296} \\ = 2 \sqrt{74} \\ = 17.2046505...$