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3 years ago

Web_assetHIDE QUESTION 7- When an organism reproduces asexually, it usually has

Chemistry

1 answer:

adelina 88 [10]3 years ago

5 0

Only one parent and the same chromosome
number as the parent.

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A large piece of iron was reacted with an acid. What would happen to the rate of the reaction had the large piece been finely di

MAXImum [283]

Answer:

D: It will increase because smaller particles provide more surface area to react.

Explanation:

When the large iron is broken up into smaller pieces, there are more places for the iron to react (meaning there's more surface area). Think of it like taking the surface area of a big cube compared to the surface area of a bunch of small cubes. The sum of the surface areas of the small cubes will be greater than that of the large cube. As a result, more places for the iron to react will cause for a greater reaction.

4 0

3 years ago

Be sure to answer all parts.

Llana [10]

Answer:

16 g has 2 sig figs

6701g has 4 sig figs

560 has 2 sig figs

Explanation:

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3 years ago

In some regions of the world, forests are cut down and then burned to create room for farmland. How might this local environment

UkoKoshka [18]

The answer is D.

Explanation

Without trees, no carbon dioxide will be released into the air. It would not raise oxygen levels, and it wouldn’t effect rising sea levels.

6 0

3 years ago

Read 2 more answers

How does temperature affect the rate of a reaction?

BaLLatris [955]

B, more kinetic energy means more collisions and thus more reactions according to collision theory.

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4 years ago

What quantity of sodium azide in grams is required to fill a 56.0 liters air bag with nitrogen gas at 1.00 atm and exactly 0 °C:

Margarita [4]

Answer:

108.6 g

Explanation:

2NaN₃(s) → 2Na(s) + 3N₂(g)

First we use the PV=nRT formula to calculate the number of nitrogen moles:

P = 1.00 atm

V = 56.0 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 0 °C ⇒ 0 + 273.2 = 273.2 K

Inputting the data:

1.00 atm * 56.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.2 K

n = 2.5 mol

Then we convert 2.5 moles of N₂ into moles of NaN₃, using the stoichiometric coefficients of the balanced reaction:

2.5 mol N₂ * $\frac{2molNaN_3}{3molN_2}$ = 1.67 mol NaN₃

Finally we convert 1.67 moles of NaN₃ into grams, using its molar mass:

1.67 mol * 65 g/mol = 108.6 g

6 0

3 years ago