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cestrela7 [59]
3 years ago
11

Web_assetHIDE QUESTION 7- When an organism reproduces asexually, it usually has

Chemistry
1 answer:
adelina 88 [10]3 years ago
5 0
<span>Only one parent and the same chromosome
number as the parent.

</span>
You might be interested in
May someone pls help me with this!
icang [17]

Answer:

Explanation:

1. Chemistry

2. Atoms

3. Anode

4. Cathode

4 0
3 years ago
0.750mol of gas are stored in a tank at a pressure of 275kpa and a temperature of 0.00 degrees * C What is the volume of the tan
nordsb [41]

Answer:

The volume on the tank is 6, 20 L

Explanation:

We use the formula PV=nRT. We convert the units of pressure in kPa into atm and temperature in Celsius into Kelvin:

0°C=273K

101,325kPa---1 atm

275kPa --------x=(275kPax 1 atm)/101,325kPa= 2,71 atm

PV=nRT --> V=nRT/P

V= 0,750 mol x 0,082 l atm /K mol x 273 K/ 2, 71 atm= <em>6, 20 L</em>

4 0
3 years ago
Argon has a pressure of 34.6 atm. It is transferred to a new tank with a volume of 456 L and pressure of 2.94 atm. What was the
NemiM [27]

Answer:

38.75 L

Explanation:

From the question,

Applying Boyles Law,

PV = P'V'....................... Equation 1

Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' =  Final Volume of Argon gas.

make V the subject of the equation

V = P'V'/P.................... Equation 2

Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.

Substitute these values into equation 2

V = (456×2.94)/34.6

V = 38.75 L

3 0
3 years ago
The specific gravity of iron is 7.87, and the density of water at 4.00
OlgaM077 [116]

The volume of 6.00g iron is 0.762 cm^3.

<em>Step 1</em>. Calculate the <em>density of Fe</em>

The <em>specific gravity</em> (SG) of a substance is the ratio of its density to the density of water at 4 °C.

SG = density of substance/density of water.

∴ 7.87 = density of iron/1.00 g·cm^(-3)

Density of Fe = 7.87 × 1.00 g·cm^(-3) = 7.87 g·cm^(-3)

<em>Step 2</em>. Calculate the <em>mass of Fe</em>

Volume of Fe = 6.00 g Fe × (1 cm^3 Fe/7.87 g Fe) = <em>0.762 cm^3</em>

8 0
4 years ago
Hello can someone help me please and thanksss
Svetlanka [38]

the equation of the parabola is given as y = 1/4 (x-6)^2 +1. D

<h3>How to find the parabola</h3>

Given the focus(6,2) and the directrix, y = 0

Use the formula

\sqrt{(x-6)^{2} + (y-2)^{2} } } = (y - 0)

Find the square of both sides, square root is removed from the side with it and square added on the other side

(x-6)^2 + (y-2)^2 = (y- 0)^{2}

Expand the expression and bring all terms to one side

x^{2} - 6x - 6x + 36 +y^{2} -2y- 2y +4 = y^{2} - 0

Collect like terms

x^{2} - 12x -4y + 40 = 0

Make 'y' the subject of the formula

4y = x^{2} - 12x + 40

Divide through by 4 and substrate 4 from 40 to give a perfect quadratic equation

y = 1/4 x^{2} - 12x + 36 + 4

Divide factor by 4 to give 1

y = 1/4( x^{2} -6x -6x +36) + 1

Simplify the expanded quadratic equation

y = x (x -6) - 6 (x- 6), we have (x - 6) ^2

Then insert in place into previous equation

y = 1/4 (x-6)^2 + 1

Thus, the equation of the parabola is given as y = 1/4 (x-6)^2 +1

Learn more about a parabola here:

brainly.com/question/4061870

#SPJ1

5 0
2 years ago
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