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Whitepunk [10]
3 years ago
12

What is a multiple of 2, 8, and 10 between 49 and 95

Mathematics
2 answers:
vovangra [49]3 years ago
7 0
80 is a number divisible by 2,8,10!
Svetlanka [38]3 years ago
5 0


4,8,16 is 64
4,8,12,16,20,24,28,32,36,40,44,48,52,56... 
<span>8,16,24,32,48,56,64,72,80,88,94 </span>
<span>16, 32, 48, 64, 80</span>
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Gelneren [198K]

Step-by-step explanation:

8.9x-5 and -6.8x+8

8.9-6.8 + -5+8

2.1x+3

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3 years ago
jack is 4 times as old as lacy. 9 years from now the sum of their ages will be 68. how old are they now?
Ierofanga [76]
The answer is 12.
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5 0
3 years ago
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5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
How I can solve this
gavmur [86]

Answer:

\boxed{\textrm{B)}\qquad y>4}.

Step-by-step explanation:

We start by subtracting 1 from both sides of the second inequality:

2x > 5 \iff 2x - 1 > 5 - 1 \iff 2x - 1 > 4.

Therefore, we conclude that:

y > 2x - 1 > 4 \implies y > 4.

Therefore, every point that satisfies the system has a y-coordinate greater than 4.

7 0
4 years ago
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