NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
c=9,50*10⁻² mol/L
Ammonia solution is a weak electrolyte.
The dissociation constant of ammonium hydroxide is:
K=1.78*10⁻⁵
[OH⁻]=√(Kc)
pH=14-pOH=14+lg[OH]⁻
pH=14+lg(√(Kc))
pH=14+lg(√(1.78*10⁻⁵*9.50*10⁻²))=8.23
pH=8.23
Answer:

Explanation:
1. Energy balance
By the first law of thermodynamics, considering the system is closed and isolated, the heat released by the 237 g piece of molybdenum equals the heat absorbed by the 244 g of water.
2. Heat equation
The heat released or absorbed by a substance is proportional to the product of the mass, the specific heat and the change in temperature
3. Heat released by the 237 g piece of molybdenum
At equilibrium:
- Q₁ = 237 g × C × (100.0ºC - 15.3ºC)
4. Heat absorbed by the 244 g of water
At equilibrium:
- Q₂ = 244 g × 4.184 J/gºC × (15.3ºC - 10.0ºC)
5. Solve for C from Q₁ = Q₂
- 237 g × C × (100.0ºC - 15.3ºC) = 244 g × 4.184 J/gºC × (15.3ºC - 10.0ºC)
- 20,073.9 × C = 5,410.7488 J/gºC
The result must be reported with 3 significant figures: C = 0.270 J/gºC.
The answer is: surface water at the poles is dense because of low temperatures and high salinity.
Answer:
A-20 B-40 C-Ca D-10 E-9 F-F