Answer:
They have the same number of valence electrons (5) so the body assumes they are the same element.
Answer:
is capable of combining with oxygen to form iron oxide
First, you need to convert kg to g.
So, 1 kg =1000g.
3.5 x 1000 = 3500g Ca(OH)2
We need to know the molar mass of Ca(OH)2.
Ca= 40.08 g
O=2(15.999)
H=2(1.0079)
Add them all together and you get 74.0938 g.
Put it in the formula from mass to moles.
# of moles = grams Ca(OH)2 x 1 mol Ca(OH)2
--------------------
molar mass Ca(OH)2
3500 g Ca(OH)2 x 1 mol Ca(OH)2
---------------------
74.0938 g Ca(OH)2
So divide 1/74.0938 and multiply by 3500.
You will get about 47.24 moles Ca(OH)2.
Hope this helps! :)
There are three number of electrons lost by 1 mole of aluminium because aluminum has +3 charge on it.
<h3>What is cation?</h3>
When an atom loses electron, positive charge appears on the atom this is called cation. In this reaction we can see that aluminium has +3 charge which means that it loses 3 electrons.
So we can conclude that There are three number of electrons lost by 1 mole of aluminium because aluminum has +3 charge on it.
Learn more about electron here: brainly.com/question/23390564
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Answer:
0.053 M is the concentration of X after 196 seconds.
Explanation:
Initial concentration of the X = ![[A_o]=1.0 M](https://tex.z-dn.net/?f=%5BA_o%5D%3D1.0%20M)
Time taken by the sample, t = 196 s
Final concentration of the X after t = [A] =?
Rate constant of the reaction = k = 
Formula used :
![[A]=[A_o]\times e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-kt%7D)
where,
Now put all the given values in this formula, we get
![[A]=[1.0M]\times e^{-1.50\times 10^{-2} s^{-1}\times 196 s}](https://tex.z-dn.net/?f=%5BA%5D%3D%5B1.0M%5D%5Ctimes%20e%5E%7B-1.50%5Ctimes%2010%5E%7B-2%7D%20s%5E%7B-1%7D%5Ctimes%20196%20s%7D)
![[A]=0.053 M](https://tex.z-dn.net/?f=%5BA%5D%3D0.053%20M)
0.053 M is the concentration of X after 196 seconds.
