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Pepsi [2]
4 years ago
5

Does the conductivity increase or decrease?

Chemistry
1 answer:
adelina 88 [10]4 years ago
5 0

Answer:

It continuously increases

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Hybridization of NH3​
nadya68 [22]

Answer:

Sp3 hybridization

Explanation:

The NH3 molecule, which consists of one lone pairs and three bond pair of electron on its valance shell due to lone pair bond pair repulsion makes bond angle of 107.5°resulting distorted tetrahedral geometry.

Hybridization =no. of bond pair +lone pair=3+1=4=sp3 hybridization

6 0
3 years ago
In the synthesis of barium carbonate from an alkali metal carbonate (M2CO3 where M is one of the alkali metals) a student genera
Paraphin [41]

Answer:

0.019 moles of M2CO3

Explanation:

M2CO3(aq) + BaCl2 (aq) --> 2MCl (aq) + BaCO3(s)

From the equation above;

1 mol of  M2CO3 reacts to produce 1 mol of BaCO3

Mass of BaCO3 formed = 3.7g

Molar mass of BaCO3 = 197.34g/mol

Number of moles = Mass / Molar mass = 3.7 / 197.34 = 0.0187  ≈ 0.019mol

Since 1 mol of M2CO3 reacts with 1 mol of BaCO3,

1 = 1

x = 0.019

x = 0.019 moles of M2CO3

3 0
3 years ago
Which basic postulates of Dalton's atomic theory are modified by the modern atomic theory​
Kisachek [45]

Answer:

Dalton's atomic theory has been modified as

Explanation:

Atoms of same element may not have same atomic mass. For example, some atoms of chlorine have atomic mass 35 amu while others have atomic mass 37 amu. Such atoms of same element having different atomic masses are called isotopes

6 0
3 years ago
Read 2 more answers
Which factor is responsible for the dry period
jeka94

Answer:

drought

Explanation:

because it looses all of the water in the aria / desertification

8 0
3 years ago
Read 2 more answers
0.72-mol sample of is put into a 1.00-L vessel and heated. At equilibrium, the vessel contains 0.40 mol of and 0.40 mol of . Cal
Dafna1 [17]

Answer:

0.50

Explanation:

<em>A 0.72-mol sample of PCl₅ is put into a 1.00-L vessel and heated. At equilibrium, the vessel contains 0.40 mol of PCl₃(g) and 0.40 mol of Cl₂(g). Calculate the value of the equilibrium constant for the decomposition of PCl₅ to PCl₃ and Cl₂ at this temperature. </em>

<em />

Step 1: Calculate the molar concentrations

[PCl₅]i = 0.72 mol/1.00 L = 0.72 M

[PCl₃]eq = 0.40 mol/1.00 L = 0.40 M

[Cl₂]eq = 0.40 mol/1.00 L = 0.40 M

Step 2: Make an ICE chart

        PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

I        0.72           0            0

C         -x            +x          +x

E      0.72-x          x           x

Step 3: Determine the value of x

Since [PCl₃]eq = [Cl₂]eq = 0.40 M, x = 0.40 M

Step 4: Determine the concentration of PCl₅ at equilibrium

[PCl₅]eq = 0.72-x = 0.72-0.40 = 0.32 M

Step 5: Calculate the equilibrium constant

Kc = [PCl₃] × [Cl₂] / [PCl₅]

Kc = 0.40 × 0.40 / 0.32 = 0.50

4 0
3 years ago
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