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lbvjy [14]
3 years ago
5

What is the chemical formula for ammonium sulfate?

Chemistry
1 answer:
Naya [18.7K]3 years ago
8 0

the formula is(NH4)2SO4

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(only reply if you know the answer or get reported) Please solve this ty​
kolezko [41]

Answer:

7) 50 8)4

Explanation:

I answered the question what do you want to gave me

4 0
3 years ago
Blank is how strong gravity pulls on an object
zheka24 [161]
It is either netforce or gforce
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3 years ago
Consider the reaction CaCO3(s) --> CaO(s) + CO2(g)
tankabanditka [31]

Answer:

Kc = [CO2], that is to say it is equal to the concentration of CO2

Explanation:

It is a heterogeneous equilibrium since the substances that participate in the reaction are in different phases

In the heterogeneous limestone decomposition reaction:

CaCO3(s) --> CaO(s) + CO2(g)

The equilibrium constants are:

Kc = [CO2(g)]; Kp = PCO2(g); Kc = Kp (R T)^ −(1−0) = Kp (R T)^ −1

The equilibrium situation is not affected by the amount of  solid or liquid, as long as these substances are present.

The equilibrium constant is independent of the  amounts of solids and liquids in equilibrium.

4 0
3 years ago
Differentiate between crystalline and amorphous solid.
Anit [1.1K]
<h2>DIFFERENCE BETWEEN CRYSTALLINE AND AMORPHOUS SOLIDS :</h2><h2><em><u> Amorphous solids do not have definite melting points but melt over a wide range of temperature because of the irregular shape. Crystalline solids, on the other hand, have a sharp melting point.</u></em></h2>
4 0
3 years ago
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You have 185 mL of an acid with an unknown concentration. To determine the concentration you decide to use a 0.85 M solution of
kondor19780726 [428]

Explanation:

The given data is as follows.

       M_{1} = ?,         M_{2} = 0.85 M

       V_{1} = 185 mL,     V_{2} = 35.7 mL

where, M_{1} is concentration of acid

            V_{1} is the volume of acid

            M_{2} is the concentration of base

            V_{2} is the volume of base

According to the neutralization formula.

          M_{1} \times V_{1} = M_{2} \times V_{2}

Now, substituting the given values into the above formula as follows.

          M_{1} \times V_{1} = M_{2} \times V_{2}

          M_{1} \times 185 mL = 0.85 M \times 35.7 mL

                       M_{1} = 0.164 M

Thus, we can conclude that concentration of acid is 0.164 M.

8 0
3 years ago
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